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inessss [21]
3 years ago
13

Round 39 to To the nearest indicated place value ten

Mathematics
2 answers:
Rufina [12.5K]3 years ago
8 0

Answer:

40

Step-by-step explanation:

That is rounded

butalik [34]3 years ago
8 0

Answer:

40

Step-by-step explanation:

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Consider the following function: f(x)= 25-x^2/x^2-4x-5 Which of the following are correct? Check all of the boxes that apply.
agasfer [191]

Answer:    B, C, and D

Step-by-step explanation:

Just did it and got the answers wrong so these are the correct ones

8 0
3 years ago
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Given FH is the median of EFG find x, EH, and HG. ​
Marianna [84]
Yeah his answer is correct Good job!
4 0
2 years ago
Use substitution to solve the<br> following system of equations.<br> - 4y - 5x = 30 AND x= y + 3
IRISSAK [1]

Answer:

The solution to the system of equations is y = -5 and x = -2.

Step-by-step explanation:

The question tells us to use substitution to solve the system.  This means that the given value for x (in terms of y) should be substituted into the other equation.  This is modeled below:

-4y - 5x = 30

-4y - 5(y+3) = 30

Next, we should use the distributive property to simplify the left side of the equation.

-4y -5y - 15 = 30

The next step is to combine like terms on the left side of the equation.

-9y - 15 = 30

Then, we can add 15 to both sides of the equation.

-9y = 45

Finally, we can divide both sides of the equation by -9.

y = -5

To find the value for x, we substitute in the value we just found for y into either of our original equations.

x = y + 3

x = -5 + 3

x = -2

Therefore, the correct answer is y = -5 and x = -2.

Hope this helps!

3 0
3 years ago
HELP ME PLEASE <br> True or false: z=−5 is a solution to the inequality −2|z−3|&lt;−20.
Dovator [93]

<em><u>your </u></em><em><u>question</u></em><em><u>:</u></em><em><u> </u></em>

<em>True or false: z=−5 is a solution to the inequality −2|z−3|<−20.</em>

<em><u>answer:</u></em><em><u> </u></em>

<em>-</em><em>2</em><em>|</em><em>z-3|</em><em><</em><em>-</em><em>2</em><em>0</em>

<em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>. </em><em> </em><em> </em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em>

<em> </em><em> </em><em> </em><em>-</em><em>2</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>-</em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>|</em><em>z-3|</em><em><</em><em>1</em><em>0</em><em> </em>

<em>equation </em><em>1</em><em>:</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>equation </em><em>2</em><em>:</em><em> </em>

<em>z-3<</em><em>1</em><em>0</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>z-3></em><em>-</em><em>1</em><em>0</em><em> </em>

z<13 z>-13

<em>So </em><em>false, </em><em>z=</em><em>-</em><em>5</em><em> </em><em>is </em><em>not </em><em>a </em><em>solution </em><em>to the </em><em>inequality</em><em>.</em>

<em>hope </em><em>this </em><em>helps, </em><em>have </em><em>a </em><em>great </em><em>day! </em><em>:</em><em>)</em>

7 0
3 years ago
The length of time a person takes to decide which shoes to purchase is normally distributed with a mean of 8.21 minutes and a st
MaRussiya [10]

Correct answer is: P(x<6) is 0.123 and it is usual.

Solution:-

Given that the time a person takes to decide which shoes to purchase follows normal distribution. Which has mean = 8.21 minutes and standard deviation 1.90

Then probability of individual takes less than 6 minutes is

P(X<6) = P(z

           = P(z

           = 0.1230

Typically we say an event with a probability less than 5% is unusual.

But here P(X<6) = 0.123 is greater than 5% hence this is usual.

4 0
3 years ago
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