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nadezda [96]
3 years ago
10

Easy question!

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
4 0

Answer: There were 38 cans in each box.

(You probably already knew the answer, but I'm bored so I'll explain it anyway).

To find the answer, you'd have to add up the total amount of cans brought into Ms. Walker's class. Since the class is composed of both girls AND boys, you'd have to add the two together.

57+57=114

Since there are three boxes, and the cans are all collectively being divided into the boxes evenly, you'd divide 114 by 3.

114/3= 38.

So, there would be 38 cans per box.

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A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions
faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3><u>Solution:</u></h3>

Given that  

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

<em><u>The area of rectangle is given as:</u></em>

\text {Area of rectangle }=length \times width

Area of rectangular parking lot = length of rectangular parking plot \times width of the rectangular parking

\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}

But it is given that Area of rectangular parking lot = 15000 square feet

\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}

Solving the above quadratic equation using quadratic formula

<em><u>General form of quadratic equation is  </u></em>

{ax^{2}+\mathrm{b} x+\mathrm{c}=0

And quadratic formula for getting roots of quadratic equation is

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}

\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet  

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0
3 years ago
Find the area of the figure by subtraction.
arsen [322]

Answer:

<em>56</em>

Step-by-step explanation:

3 0
3 years ago
Let the function f be defined as f(x)= 5x^2 - 7(4x+3). What is the value of f(3)
Katen [24]

Answer:

f(x) = -60 is your answer

Step-by-step explanation:

Plug in 3 for x

f(x) = 5x² - 7(4x + 3)

f(x) = 5(3²) - 7(4(3) + 3)

Follow PEMDAS. First, solve the parenthesis

3² = 9

4(3) + 3 = 12 + 3 = 15

f(x) = 5(9) - 7(15)

Multiply

f(x) = 45 - 105

Simplify. Subtract

f(x) = 45 - 105

f(x) = -60

f(x) = -60 is your answer

~

4 0
3 years ago
Please tell me the final answer and how you got it.
dem82 [27]
It is  484 m^2 ,to my understanding!
5 0
3 years ago
A bowl of berries contains 2 strawberries, 4 blackberries, 1 raspberry, and 3 blueberries Loue will randomly select two berries
Sunny_sXe [5.5K]

Answer

b

Step-by-step explanation:

3 0
3 years ago
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