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Nastasia [14]
3 years ago
14

I wanted to know what 1 + 1 equals.

Mathematics
2 answers:
lord [1]3 years ago
8 0

Answer:

D.A.M.N thats really hard idk either i think its 12 not sure tho

Step-by-step explanation:

hope this helps

fiasKO [112]3 years ago
3 0

Answer:

Im sorry but I want to know what grade ur in?

hope this help!!!!

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Not the best at this! Can someone please help me ?!
umka2103 [35]

Answer:

1= 2x+11

2= is none of those

3= √x^2 –11

4= √2x+11

Step-by-step explanation:

5 0
3 years ago
Use the commutative and associative properties of multiplication to write an expression equivalent to (4⋅5)⋅3.
Darina [25.2K]
Commutaive property says
ab=ba or expanded to say
abc=cba

associative peropty =
a(bc)=(ab)c

so using that
first mix them up knowing that we can move the parenthaseese
all possible equivelnt ones are
4*(5*3)
(3*5)*4
3*(5*4)
(3*4)*5
3*(4*5)
 
4 0
3 years ago
True or False, the following numbers are in order from greatest to least:<br> 11/10, 8/7,-2.34*
rjkz [21]

Answer:

fasle

Step-by-step explanation:

6 0
4 years ago
The slope of a line is 2, and the y-intercept is 0. What is the equation of the line written in slope-intercept form?
Orlov [11]
The equation y=mx+b
Slope= m
y-intercept= b

y= 2x+0 so y=2x
7 0
4 years ago
Find f.<br><br> A) 7.4<br><br> B) 8.2<br><br> C) 10.5<br><br> D) 11.1
tatyana61 [14]
F=72

g=6

------------

\cos { \left( F \right)  } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }

Therefore:

\cos { \left( 72 \right)  } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right)  } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }

\\ \\ 12e\cdot \cos { \left( 72 \right)  } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right)  } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 }  } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right)  }  \right) +36 }

But what is e?

E=76

G=32

g=6

And:

\frac { e }{ \sin { \left( E \right)  }  } =\frac { g }{ \sin { \left( G \right)  }  }

Which means that:

\frac { e }{ \sin { \left( 76 \right)  }  } =\frac { 6 }{ \sin { \left( 32 \right)  }  } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right)  }  }{ \sin { \left( 32 \right)  }  }

If you take this value into account, you will discover that f is...

f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right)  }  }{ \sin { \left( 32 \right)  }  } \left( \frac { 6\cdot \sin { \left( 76 \right)  }  }{ \sin { \left( 32 \right)  }  } -12\cos { \left( 72 \right)  }  \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)

So I would have to say that the answer is approximately (c).
6 0
3 years ago
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