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3 years ago

Perpendicular lines do not intersect. True or false?

Mathematics

2 answers:

saul85 [17]3 years ago

4 0

Answer:

Perpendicular lines are lines that intersect at a right (90 degrees) angle

Step-by-step explanation:

Gwar [14]3 years ago

4 0

Answer:

This is true because it is 90% i hope this helped and if you have anymore questions don't be afraid or embarrassed about asking questions

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during the 31 nights of October , Keith kept track of his sleep. he slept a total of 297 hours . How many hours of sleep did he

love history [14]

297/31 = 9.6 hours

i think

3 0

3 years ago

A 12-member jury is to be selected from 15 men and 13 women. Find the probability that this jury has 6 or 7 males.

Bas_tet [7]

Answer:

The right solution is "0.5545".

Step-by-step explanation:

According to the question,

The probability of having 6 or 7 males will be:

= $P(6 \ males)+ P(7 \ males)$

= $\frac{15_C_6\times 13_C_6}{28_C_{12}} + \frac{15_C_7\times 13_C_5}{28_C_{12}}$

= $\frac{5005\times 1716+6435\times 1287}{30421755}$

= $\frac{16870425}{30421755}$

= $0.5545$

8 0

3 years ago

What is the domain and range for:<br> y = arcsin(tanx)

Semmy [17]

The graph looks like this, on the enclosed pic:
One feature is that it's periodic and torn (has cut-off points), meaning the domain is the same as in case of tan(x): x€R and x =/= π/2+πn.
The range equals the range of arcsin(x): -π/2<=y<=π/2 OR y€[-π/2;π/2]
Hope could understand and if it helped! :)

7 0

3 years ago

Solve the following quadratic equation by completing the square ✓3x^2 + 10x + 7✓3 = 0

solmaris [256]

$\sqrt{3}x^2+10x+7\sqrt{3}=0\\\\\sqrt3(x^2+\dfrac{10x}{\sqrt{3}}+7)=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+7=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+\dfrac{25}{3}-\dfrac{25}{3} +7=0\\\\(x+\dfrac{5}{\sqrt{3}})^2 = \dfrac{4}{3}\\\\|x+\dfrac{5}{\sqrt{3}}| = \dfrac{2}{\sqrt{3}}\\\\x_1 = \dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = -\dfrac{3}{\sqrt{3}} = -\sqrt{3}\\\\x_2 = -\dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = \dfrac{-7}{\sqrt{3}} = -\dfrac{-7\sqrt{3}}{3}$

5 0

3 years ago

In a soccer game, Sally kicks the ball to a teammate who is on the other side of the field. The ball's height h (in feet above t

Katena32 [7]

Answer: 0

Step-by-step explanation:

h ( t ) = − 2 t ^2 + 10 t

h = height of ball above the ground

t = time, seconds after ball was kicked

Height of ball at the time it is kicked?

At the time ball is kicked, time (t) = 0

Therefore,

h ( t ) = − 2 t ^2 + 10 t

h( 0) = - 2(0)^2 + 10(0)

h = 0 + 0

h = 0

The ball was the on the grounf at the time it was kicked.

6 0

3 years ago