Answer:
a) X[bar]₁= 1839.20 cal
b) X[bar]₂= 1779.07 cal
c) S₁= 386.35 cal
Step-by-step explanation:
Hello!
You have two independent samples,
Sample 1: n₁= 15 children that did not eat fast food.
Sample 2: n₂= 15 children that ate fast food.
The study variables are:
X₁: Calorie consumption of a kid that does not eat fast food in one day.
X₂: Calorie consumprion of a kid that eats fast food in one day.
a)
The point estimate of the population mean is the sample mean
X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal
b)
X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal
c)
To calculate the sample standard deiation, you have to calculate the sample variance first:
S₁²= 
[∑X₁² - (( ∑X₁)²/n₁)]= 
= 149263.4571 cal²
S₁= 386.35 cal
I hope it helps!
Answer:
<em>Direction of the boat is 43.05° and the speed is 21.66 knot</em>
<em></em>
Step-by-step explanation:
yacht speed = 20 knots
yacht bearing = 185° = 85° below the negative horizontal x-axis
wind speed = 15 knots
wind bearing = 290° = 20° above the negative horizontal x-axis
we find the x and y components of the boat velocities
for yacht,
x component = -20 cos 85° = -1.74 knots
y component = -20 sin 85° = -19.92 knots
for the wind,
x component = -15 cos 20° = -14.09 knots
y component = 15 sin 20° = 5.13 knots
total x component Vx = -1.74 + (-14.09) = -15.83 knots
total y component Vy = -19.92 + 5.13 = -14.79 knots
Resultant speed of the boat = 
==> 
= <em>21.66 knot</em>
<em></em>
direction of boat = 
==> 
= <em>43.05°</em>
Hello :
<span>–9.5 + 6x ≥ 42.1
6x </span>≥ 42.1 + 9.5
6x ≥ 51.6
x ≥ 51.6/6
x ≥ 8.6
using interval notation: <span>[8.6 ; +∞[ </span>
Answer:
1/2x
Step-by-step explanation:
Trust me bro lol
