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3 years ago

2. a² + b2 = c2 a=9 b=40

1 answer:

3 0

I don’t know if you meant b^2 and c^2 or b x 2 and c x 2 so I’ll do both.

If it’s meant to be multiplied by 2, then you do 9^2 + (40)2 =c2

81 + 80 = c2

161 = c2
/2
80.5 = c

However I do doubt it’s that. This means it’s likely meant to be squared instead. In which case, use the following answer.

9^2 + 40^2 =c^2

1681 = c^2

Then square root both sides to get just c (which i assume is what you’re trying to find?)

Square root of 1681 = 41

So your answer would be 41.

You might be interested in

Becky's ship is 43 miles west all the harbor.

pishuonlain [190]

Answer:

Clyde is 49.74 away from the harbor

Step-by-step explanation:

Here in this question, we are interested in knowing the distance of Clyde from the harbor.

The key to answering this question is having a correct diagrammatic representation. Please check attachment for this.

We can see we have the formation of a right angled triangle with the distance between Clyde’s ship and the harbor the hypotenuse.

To calculate the distance between the two, we shall employ the use of Pythagoras’ theorem which states that the square of the hypotenuse is equal the sum of the squares of the two other sides.

Let’s call the distance we want to calculate h.

Mathematically;

h^2 = 25^2 + 43^2

h^2 = 625 + 1849

h^2 = 2474

h = √2474

h = 49.74 miles

5 0

3 years ago

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

2 years ago

If x and y are 2 complementary angles then find the value of y if measure of angle x is 20 degree

schepotkina [342]

Answer:

y=70 degrees

Step-by-step explanation:

If 2 angles are complimentary, they add up to 90 degrees.

x+y=90 degrees

x=20 degrees

y=90-20 degrees

y=70 degrees

If that is wrong, try this. Let's say the questions gives us the fact that x is 20 degrees greater than y.

y=x

Substituting x for y, the equation is x+x+20=90

Since y is x, x would also be y, which is 35. then x+20 would be 55.

So y would be 35.

THE ANSWER WOULD BE <u><em>70 DEGREES</em></u>, BUT IF THAT IS WRONG, DO THE SECOND ONE, WHICH IS 35

6 0

3 years ago

Hel0 me please, please please

Simora [160]

Answer:

The answer would be 0

Step-by-step explanation:

Go to symbolab.com and just put the equation in

8 0

3 years ago

5 less than the quotient of a number and 3 is -7

hram777 [196]

$\frac{x}{3}$ - 5 = -7 .
____________________________________________
This would be one way to write the expresion/equation; in which "x" represents the unknown number.

Now, to solve for "x" ;
____________________________________________
Given:
____________________________________________
$\frac{x}{3}$ - 5 = -7 ;

Add "5" to EACH SIDE of the equation:
_____________________________________________
$\frac{x}{3}$ - 5 + 5 = -7 + 5 ;

to get:

$\frac{x}{3}$ = -2 ;

x = (-2 * 3) ;
_________________________________
x = - 6 .
_________________________________

6 0

3 years ago