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Tems11 [23]
4 years ago
9

A set of data with 100 observations has a mean of 267. There are six outliers in the data set, which have a mean of 688. If the

six outliers are removed, what is the mean of the new data set?
A. 251.0
B. 311.6
C. 240.1
D. 284.0
Mathematics
2 answers:
yuradex [85]4 years ago
8 0

Let

x------> the sum of a set of data with 100 observations

Mn------> the means of the new data set

we know that

\frac{x}{100}=267\\  \\ x=267*100\\ x=26,700

Mn=\frac{(x-6*688)}{(100-6) }\\ \\ Mn=\frac{(26,700-4,128)}{(94) }\\ \\ Mn=240.13

therefore

the answer is the option C

the mean of the new data set is 240.1

Mnenie [13.5K]4 years ago
3 0
X*94 +688*6  = 267*100
94x+4128=26700     
94X=22572    /94
X=240.128
C is the closest answer
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3 years ago
Read 2 more answers
2^-3 x 3^-2<br> 2 to the power of negative 3 times by 3 to the power of negative 2
Ivan
<h3>The value of 2 to the power of negative 3 times by 3 to the power of negative 2 is 0.013889</h3>

<em><u>Solution:</u></em>

<em><u>Given that:</u></em>

2^{-3} \times 3^{-2}

We have to find the value of expression

We know that,

a^{-n} = \frac{1}{a^n}

Therefore,

2^{-3} \times 3^{-2} = \frac{1}{2^3} \times \frac{1}{3^2}

We know that,

a^2 = a \times a

Similarly,

2^{-3} \times 3^{-2} = \frac{1}{2 \times 2 \times 2} \times \frac{1}{3 \times 3}\\\\Simplify\\\\2^{-3} \times 3^{-2} = \frac{1}{8} \times \frac{1}{9}\\\\2^{-3} \times 3^{-2} = \frac{1}{72}\\\\Simplify\\\\2^{-3} \times 3^{-2} = 0.013889

Thus value of 2 to the power of negative 3 times by 3 to the power of negative 2 is 0.013889

5 0
3 years ago
Can someone help solve this
kap26 [50]

Answer:

336 cubic cm

Step-by-step explanation:

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V (cone) = (πr^{2}h)/3

               = π4^{2}(12) ÷ 3

               = 64π  ≈ 201 cm

V (sphere) = 4/3πr^{3}/2

               = [4/3π(4^3)] ÷ 2

               = (256π/3) ÷ 2

               ≈ 43π ≈ 135

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3 years ago
How who I complete the table?
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Answer:

6

7

8

10

Step-by-step explanation:

you have to remove // to calculate

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4 years ago
A(c-b)=d
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B) the answer is b i did this
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3 years ago
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