Given that
log (x+y)/5 =( 1/2) {log x+logy}
We know that
log a+ log b = log ab
⇛log (x+y)/5 =( 1/2) log(xy)
We know that log a^m = m log a
⇛log (x+y)/5 = log (xy)^1/2
⇛log (x+y)/5 = log√(xy)
⇛(x+y)/5 = √(xy)
On squaring both sides then
⇛{ (x+y)/5}^2 = {√(xy)}^2
⇛(x+y)^2/5^2 = xy
⇛(x^2+y^2+2xy)/25 = xy
⇛x^2+y^2+2xy = 25xy
⇛x^2+y^2 = 25xy-2xy
⇛x^2+y^2 = 23xy
⇛( x^2+y^2)/xy = 23
⇛(x^2/xy) +(y^2/xy) = 23
⇛{(x×x)/xy} +{(y×y)/xy} = 23
⇛(x/y)+(y/x) = 23
Therefore, (x/y)+(y/x) = 23
Hence, the value of (x/y)+(y/x) is 23.
Answer:
-9x+12
Step-by-step explanation:
(-8x + 5) - (x – 7)
Distribute the minus sign
(-8x + 5) - x + 7
Combine like terms
(-8x -x+ 5+7)
-9x +12
Answer: 10 km/ hr
Step-by-step explanation:
In the graph below, Diego's speed at various points during his 10 kilometer race is shown on the y axis while the distance is shown on the x axis.
Looking at the 1km mark on the x axis, Diego's speed on the y-axis is at 10km/ hr and this was the speed he started the race with. After the kilometer mark however, his speed changed and went on to increase to 11km/ hr by the second kilometer mark.