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3 years ago

10

Emma needs to find the surface area of a triangular pyramid where the base and all three faces are congruent equilateral triangl

es.
What is the total surface area?

1 answer:

Alex17521 [72]3 years ago

4 0

Answer:

73.19

Step-by-step explanation:

4 * (1/2)* (6.5) * (5.63)

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£28 call out charge +£16 for each half hour he spends on the repair .

Juliette [100K]

Answer: $76 will be the total for one and a half ours for a repair.

Step-by-step explanation:

28 + 16hh

hh = half hour

1 and a half hours = 3 half hours

28 + 16(3)

28 + 48 = 76

8 0

4 years ago

Question 3 <br><br> Find FS If BS =16 .

lys-0071 [83]

Answer:

FS = 48

Step-by-step explanation:

The distance from the vertex to the centroid is twice the distance from the centroid to the midpoint, so

FB = 2 BS = 2 × 16 = 32

Then

FS = FB + BS = 32 + 16 = 48

8 0

3 years ago

9 and 3/4 As a improper fraction

Mrrafil [7]

Answer:

The improper fraction is 39/4.

Step-by-step explanation:

9 3/4 = 36 + 3 / 4

= 39/4

Thus the improper fraction is 39/4.

Hope I helped!

6 0

4 years ago

Read 2 more answers

Please answer this correctly

BlackZzzverrR [31]

Answer:

9.5 ft

Step-by-step explanation:

The perimeter is equal to

P =2(l+w)

29.6 = 2(5.3+z)

Divide each side by 2

29.6 /2 =2/2(5.3+z)

14.8 = 5.3 +z

Subtract 5.3 from each side

14.8-5.3 = z

9.5 =z

8 0

3 years ago

Read 2 more answers

*Be sure to simplify fractions and rationalize denominators if necessary.

m_a_m_a [10]

As given by the question

There are given that the vector:

$\vec{v}=\vec{2i}+\vec{3j}$

Now,

From the formula to find the unit vector in same direction is:

$\vec{u}=\frac{\vec{v}}{\lvert\vec{v}\rvert}$

Then,

$\begin{gathered} \vec{u}=\frac{\vec{v}}{\lvert\vec{v}\rvert} \\ \vec{u}=\frac{\vec{2i}+\vec{3j}}{\lvert\vec{2i}+\vec{3j}\rvert} \\ \vec{u}=\frac{\vec{2i}+\vec{3j}}{\lvert\sqrt[]{2^2+3^2}\rvert} \end{gathered}$

Then,

$\begin{gathered} \vec{u}=\frac{\vec{2i}+\vec{3j}}{\sqrt[]{2^2+3^2}} \\ \vec{u}=\frac{\vec{2i}+\vec{3j}}{\sqrt[]{4+9}} \\ \vec{u}=\frac{\vec{2i}+\vec{3j}}{\sqrt[]{13}} \end{gathered}$

Then,

Rationalize the denominator:

So,

$\begin{gathered} \vec{u}=\frac{\vec{2i}+\vec{3j}}{\sqrt[]{13}} \\ \vec{u}=\frac{\vec{2i}+\vec{3j}}{\sqrt[]{13}}\times\frac{\sqrt[]{13}}{\sqrt[]{13}} \\ \vec{u}=\frac{\vec{\sqrt[]{13}(2i}+\vec{3j})}{13} \\ \vec{u}=\frac{2\sqrt[]{13}}{13}i+\frac{3\sqrt[]{13}}{13}j \end{gathered}$

Hence, the unit vector is shown below:

$\vec{u}=\frac{2\sqrt[]{13}}{13}i+\frac{3\sqrt[]{13}}{13}j$

6 0

2 years ago