All categories

2 years ago

E/2=3 please help ASAP

Mathematics

2 answers:

nordsb [41]2 years ago

8 0

Answer:

E= 6

Step-by-step explanation:

6/2 = 3

hope this helped!

Kruka [31]2 years ago

4 0

Answer:

As per as the given equation

E/2=3

E=3*2

E=6

You might be interested in

Help me please Ghvhbhbgv

worty [1.4K]

Answer:

8100000*3= 24 300 000

8 0

3 years ago

Read 2 more answers

Equivalent ratio for 10/24 PLEASE NOW HURRY

Luden [163]

Step-by-step explanation:

fraction 10/24

you want the ratio

answer is 5:12

if you want the explanation look below

Step One: Reduce the fraction

10/24

5/12

Step Two: Rewrite as a ratio

5/12 = 5 : 12

6 0

3 years ago

Read 2 more answers

Y''+y'+y=0, y(0)=1, y'(0)=0

mars1129 [50]

Answer:

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form $ay''+by'+cy=0$ .

Given: $y''+y'+y=0$

Let $y=e^{rt}$ be it's solution.

We get,

$\left ( r^2+r+1 \right )e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2+r+1=0$

{ we know that for equation $ax^2+bx+c=0$ , roots are of form $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ }

We get,

$y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}$

For two complex roots $r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta$ , the general solution is of form $y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )$

i.e $y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Applying conditions y(0)=1 on $e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$ , $c_1=1$

So, equation becomes $y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

On differentiating with respect to t, we get

$y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )$

Applying condition: y'(0)=0, we get $0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}$

Therefore,

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

3 0

3 years ago

At a train station, freight trains depart at a rate of 2 trains every 30 minutes and passenger trains depart at a rate of 1 trai

never [62]

In my work I used t=trains and m=minutes:
30+30= 60m/2t
30+30= 60m/2t
30+30= 60m/2t
30+30= 60m/2t
30+30= 60m/2t
30+30= 60m/2t
30+30= 60m/2t
30+30= 60m/2t
30+30= 60m/2t
30+30= 60m/2t
30+30= 60m/2t
30+30= 60m/2t
Total= 720m/24t

1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30= 4 o' clock
Total= 372m/12t

24t+12t= 36t

The answer is:
36 trains in total

6 0

3 years ago

Chan is filling a box with 1-inch cubes. He filled the bottom layer as shown. Chan wants to completely fill the box. How many cu

IceJOKER [234]

The answer is D 174 cubes.

3 0

3 years ago