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Hunter-Best [27]
3 years ago
6

The diameter of a circle is 4 cm. Find its area to the nearest tenth.

Mathematics
2 answers:
vazorg [7]3 years ago
8 0
Pretty sure it’s 40 yep
Nutka1998 [239]3 years ago
5 0

Answer:

10 cm²

Step-by-step explanation:

The radius of this circle is half the diameter hence is 2cm

Area of a circle is pi multiplied by the squared radius, i.e

Area = πr²

= 22/7 × 2 × 2

= 12.57 cm²

The nearest 10th is 10

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Answer:

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Step-by-step explanation:

Centre (h,k) = (0,-8)

radius (r) = 9

(x - h)² + (y - k)² = r²

(x - 0)² + (y + 8)² = 9²

x² + (y + 8)² = 81

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3 years ago
A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for
Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

\implies h=\frac{1}{w^2}

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

= 2\times \frac{1}{w^2}(w+2w)

=\frac{6w}{w^2}

=\frac{6}{w}  

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}

=2w^2+4w^2+\frac{12}{w}

=6w^2+\frac{12}{w}

Differentiating with respect to w,

C'(w) = 12w -\frac{12}{w^2}

Again differentiating with respect to w,

C''(w) = 12 + \frac{24}{w^3}

For maxima or minima,

C'(w) = 0

\implies 12w -\frac{12}{w^2}=0

\implies 12w^3 - 12=0

w^3-1=0\implies w = 1

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0
3 years ago
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