Answer:
W=2001.24 newton meters
Caution: check units and arithmetic - I often make errors.
Step-by-step explanation:
Work is force times distance.
Denote height by h where h=0 is at ground level.
Denote the mass of the bucket and rope at height h by m(h).
The rate at which the bucket loses mass with height is (20-16)/10=0.4 kg/m
The rate at which the rope between the bucket and the top of the building loses mass is 0.4 kg/m
The initial mass of the bucket and rope is
![m_{0}=20+0.4+0.4(10)=24.4](https://tex.z-dn.net/?f=m_%7B0%7D%3D20%2B0.4%2B0.4%2810%29%3D24.4)
The mass at height h is
![m(h)=24.4-0.8h](https://tex.z-dn.net/?f=m%28h%29%3D24.4-0.8h)
The force required at height h is
m(h)g
where g is the gravitational acceleration.
g=9.81 meters/sec/sec
The work required is
![\int\limits^b_a {m(h)g} \, dh](https://tex.z-dn.net/?f=%5Cint%5Climits%5Eb_a%20%7Bm%28h%29g%7D%20%5C%2C%20dh)
Where a=0 and b=10
![g\int\limits^b_a {(24.4-0.8h)} \, dh=g(24.4h-0.4h^2)\left \{ {{10} \atop {0}} \right.](https://tex.z-dn.net/?f=g%5Cint%5Climits%5Eb_a%20%7B%2824.4-0.8h%29%7D%20%5C%2C%20dh%3Dg%2824.4h-0.4h%5E2%29%5Cleft%20%5C%7B%20%7B%7B10%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.)
g(244-40)=204g
W=2001.24 newton meters
Answer:
15
Step-by-step explanation:
You seem to say that y=15, so, wouldn't that be the new value?
Answer:
yay! :D
Step-by-step explanation:
1: 4 8 12 16 20 and so on.
2: 7 14 21 28 35
3: 9 18 27 36 45
4: 12 24 36 48 60
your basically going and times the number 1, 2, 3, 4, and 5 times.
Answer:
What? I’m 15
Step-by-step explanation: