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Grace [21]
3 years ago
12

A computer printer can print 10 pages per minute.

Mathematics
1 answer:
lianna [129]3 years ago
5 0

Answer:

what's the question though ?

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When the angle of elevation to the sun is 42 a flagpole casts a shawdow that is 21 ft long
podryga [215]
:):):):):):):):):):):):
7 0
3 years ago
PLEASE HELPPP MEEEEEEEEEEE I DK THIS-
Julli [10]

Answer:

FOr the first one you can do:

y= -x +4

y= -x+2

y = -x

y= -x-2

y = x-4

Step-by-step explanation:

I'll do the second one in a different answer use these for now.

8 0
2 years ago
In a​ survey, 400 people were asked to choose one card out of five cards labeled 1 to 5. The results are shown in the table. Com
-BARSIC- [3]

Answer:

The value of the experimental probability is greater

Step-by-step explanation:

For the theoretical probability;

the probability that a card with the number 3 is selected is 1/5

We consider that the probabilities of each selection are equal, for the theoretical probability

For the experimental, we simply place the frequency of the selection 3 over the total

that will be 128/400 = 8/25

As we know that 8/25 is greater than 1/5

We can conclude that the value of the experimental probability is greater than that of the theoretical

6 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (4, 8) and (-3, 1)?
blondinia [14]

Answer:

1

Step-by-step explanation:

6 0
3 years ago
Cobalt-56 has a decay constant of 8.77 × 10-3 (which is equivalent to a half life of 79 days). How many days will it take for a
sweet-ann [11.9K]
As I read this one, is just a decay exponential equation... so

A = P(1 + r)ᵗ   where "t" is days passed. . hmm in this case is decay, so negative rate  A = P(1 - r)ᵗ, and the decimal amount would be 0.00877 for the rate

62% of P, the original value, is just 0.62P, now... if we hmm take P as just 1, it could be any amount, but 62% of 1,000,000 is just 62% of 1 times 1,000,000

so, for the sake of comparing it with a percentage, 1 will do

\bf 0.62P=P(1-0.00877)^t\implies P=1\implies 0.62=(1-0.00877)^t
\\\\\\
ln(0.62)=ln[(1-0.00877)^t]\implies ln(0.62)=t\cdot  ln(1-0.00877)
\\\\\\
\cfrac{ln(0.62)}{ln(0.99123)}=t
7 0
3 years ago
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