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Andre45 [30]
3 years ago
9

How do i add 21p to 35q

Mathematics
2 answers:
mariarad [96]3 years ago
7 0
I don't think you can because the variables are different. You can only add the same variables.
kvv77 [185]3 years ago
5 0
You can't add 21p + 35q because the variables are different. So 21p + 35q = 21p + 35q. If 35q was 35p we could have added like this:-

21p + 35p 
(27 + 35)p 
62p  

Or if it was 21q instead of 21p we could have added like this:-

21q + 35q
(21 + 35)q
62q

So, you can NOT add 21p to 35q.

Hope I helped ya!! xD 
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Operations with Radical Expressions
lisov135 [29]

Answer: 30\sqrt{11}

<u>Step-by-step explanation:</u>

  3\sqrt{50} * \sqrt{22}

= 3\sqrt{5*5*2} * \sqrt{2*11}

= 3\sqrt{5*5*2*2*11}

= 3*5*2\sqrt{11}

= 30\sqrt{11}

******************************************

Answer: 6\sqrt{30}

<u>Step-by-step explanation:</u>

  \sqrt{20} * \sqrt{3} * \sqrt{18}

= \sqrt{2*2*5} * \sqrt{3} * \sqrt{3*3*2}

= \sqrt{2*2*5*3*3*3*2}

= 2*3\sqrt{5*3*2}

= 6\sqrt{30}

********************************************

Answer: -\sqrt{5}

<u>Step-by-step explanation:</u>

  4\sqrt{20} - 3\sqrt{45}

= 4\sqrt{2*2*5} - 3\sqrt{3*3*5}

= 4*2\sqrt{5} - 3*3\sqrt{5}

= 8\sqrt{5} - 9\sqrt{5}

= -\sqrt{5}

********************************************

Answer: 4\sqrt{5}

<u>Step-by-step explanation:</u>

  2\sqrt{5} + 3\sqrt{5} - \sqrt{5}

= (2+3-1)\sqrt{5}

= 4\sqrt{5}

********************************************

Answer: 46\sqrt{2}

<u>Step-by-step explanation:</u>

  4\sqrt{32} + 6\sqrt{50}

= 4\sqrt{2*2*2*2*2} + 6\sqrt{2*5*5}

= 4*2*2\sqrt{2} + 6*5\sqrt{2}

= 16\sqrt{2} + 30\sqrt{2}

= 46\sqrt{2}





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