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labwork [276]
3 years ago
6

Solve using quadratic formula Show work/explain X^2 - 2x - 24 = 0

Mathematics
1 answer:
Likurg_2 [28]3 years ago
4 0

See the attached picture:

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8.1 + 2.53<br><br><br> help<br> help
Bingel [31]

Answer: 10.63

Step-by-step explanation: 8.1 + 2.53

7 0
3 years ago
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21. In 4 + In(4x - 15) = In(5x + 19)
Alexxx [7]

Answer:

x=-30;\quad \:I\ne \:0

Step-by-step explanation:

In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)

\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\

\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\

\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:

\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0

3 0
3 years ago
Factor the polynomial completely. Use synthetic division. <br><br> F(x) = x^3-7x-6
aleksklad [387]

Answer:

The factors of given polynomial    x =-1 , -2 and x =3

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given the polynomial  

                    f(x) =  x³ - 7x -6

 put x =-1

               f(-1) = (-1 )³- 7(-1) - 6 = -1+7-6=0

(x+1) is a one factor

By using synthetic division

                   x³    x²      x      constant

     x=-1  ↓   1      0      -7        -6

             <u>↓   0     -1      1          6</u>

            <u>       1       -1      -6       0     </u>

<u />

<em>The polynomial    x² - x - 6 </em>

<u><em>Step(ii):-</em></u>

The factors ( x+1)(x² - x - 6 ) = 0

     x = -1 and x² - x - 6 =0

    x =-1    and  x² - 3x + 2 x - 6 =0

   x =-1     and  x (x -3) + 2( x-3) =0

   x =-1     and  (x+2)(x-3) =0

<u><em>Final answer:-</em></u>

The factors of given polynomial    x =-1 , -2 and x =3

6 0
3 years ago
Simplify this expression <br> 7z+5+6z-9
Simora [160]

Answer:

7z + 5 + 6z - 9  (Add 7z and 6z, subtract 9 from 5)

<em>13z - 4  </em>(Can't be simplified further)

8 0
3 years ago
Some help please? <br><br><br> Which polynomial represents the difference below?
Helga [31]

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4 0
3 years ago
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