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Evgen [1.6K]
2 years ago
8

Mrs. Taylor is planning a pizza party for her students. She plans to purchase cheese pizza and pepperoni pizza for her students

to enjoy. Cheese pizzas cost $8 each and pepperoni pizzas cost $11 each. She needs to purchase at least 12 pizzas, while spending no more than $180.
What are two combinations of cheese and pepperoni pizzas that Mrs. Taylor can purchase without exceeding her spending limit?

Let x represent the number of cheese pizzas purchased and y represent the number of pepperoni pizzas purchased.
Mathematics
1 answer:
lys-0071 [83]2 years ago
5 0

Answer:

Step-by-step explanation:

She needs 12 pizzas

x + y = 12

She also can't spend more than 180 dollars.

8x + 11y < 180 She can get all 12 pizzas and have the bill come to 132 dollars

11 * 12 = 132

She could really be kind to her pocket book and get all cheese pizzas

8*12 = 96 which saves her 36 dollars.

So any number of either kind will do.

(0,12) = 132

(1,11) = 8*1 + 11*11 = 129

and so on down the line

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Subtract the following:

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B) 49 rupees 79 paise from 123 rupees 68 paise.

Answer

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Hint: Use decimal concept.

We know that, 1 rupee = 100 paise. We can reframe these questions as follows:

18 rupees 9 paise from 75 rupees 80 paise

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 here help u  3/5

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