I can’t read it i need my glasses but i lost them do you know where they are?
Answer;
DNA replication is semi-conservative.
The meselson-stahl experiment supported the hypothesis that DNA replication is semi-conservative.
Explanation;
The Meselson-Stahl experiment was an experiment by Meselson and Stahl that proved that the semi-conservative model by Watson and Crick was correct.
DNA replication is semi-conservative in the sense that the new helices formed after replication contain, one new DNA strand and one old strand from the parent DNA molecule.
Answer:
Step 1. A carboxyl group is removed from pyruvate, releasing a molecule of carbon dioxide into the surrounding medium. (Note: carbon dioxide is one carbon attached to two oxygen atoms and is one of the major end products of cellular respiration. ) The result of this step is a two-carbon hydroxyethyl group bound to the enzyme pyruvate dehydrogenase; the lost carbon dioxide is the first of the six carbons from the original glucose molecule to be removed. This step proceeds twice for every molecule of glucose metabolized (remember: there are two pyruvate molecules produced at the end of glycolysis); thus, two of the six carbons will have been removed at the end of both of these steps.
Step 2. The hydroxyethyl group is oxidized to an acetyl group, and the electrons are picked up by NAD+, forming NADH (the reduced form of NAD+). The high- energy electrons from NADH will be used later by the cell to generate ATP for energy.
Step 3. The enzyme-bound acetyl group is transferred to CoA, producing a molecule of acetyl CoA. This molecule of acetyl CoA is then further converted to be used in the next pathway of metabolism, the citric acid cycle.
Both A and B are correct.
