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3 years ago

Will give out Brainliest, aTHX, a friend request, and will rate ur answer

Mathematics

1 answer:

IgorC [24]3 years ago

6 0

Answer:

a. -1

b. 8

c. 3

Step-by-step explanation:

6-7

(factor out the negative sign)

-(7-6)

(calculate)

-1

(your answer)

6-(-2)

(remove the parentheses)

6+2

(calculate)

(your answer)

6-3=3

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No solution.

Step-by-step explanation:

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SCORPION-xisa [38]

Answer:

68 people

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3 years ago

Taylor, Moore, and Jenkins are candidates for public office. It is estimated that Moore and Jenkins have about the same probabil

katrin [286]

Answer:

Taylor = 50%

Moore = 25%

Jenkins = 25%

Step-by-step explanation:

Assuming there are no other candidates and that someone has to win the election, the probabilities of Taylor, Moore, and Jenkins winning the election must add up to 1 or 100%.

$T+M+J = 1\\$

Since Moore and Jenkins have about the same probability of winning, and Taylor is believed to be twice as likely to win as either of the others:

$M=J\\T=2J\\J+J+2J=1\\J=0.25\\M=J=0.25\\T=2*0.25=0.5$

Taylor has a probability of 50% of winning the election.

Moore has a probability of 25% of winning the election.

Jenkins has a probability of 25% of winning the election.

3 0

3 years ago

The equation a company uses to

crimeas [40]

The equation solved for s is s = 4p - 48h

Solution:

Given that equation a company uses to calculate pay checks is p = 12h +0.25s

Therefore the given equation is:

p = 12h + 0.25s

Where "h" is the number of hours worked

"s" is the total sales

To find: equation for "s"

Let us solve the given equation for "s"

p = 12h + 0.25s

Now move 12h from R.H.S to L.H.S

p - 12h = 0.25s

Now move from 0.25 from R.H.S to L.H.S

$s = \frac{p-12h}{0.25}\\\\s = \frac{p}{0.25} -\frac{12h}{0.25}$

We know that, $0.25 = \frac{1}{4}$

$s = \frac{p}{\frac{1}{4}} -\frac{12h}{\frac{1}{4}}\\\\s = p \times \frac{4}{1} - 12h \times \frac{4}{1}\\\\s = 4p - 48h$

Thus the equation for s is s = 4p - 48h

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3 years ago

If a household has at least one cat, there is a 30% probability that the household has at least one dog. thirty percent of house

Lena [83]

The probability that the same household that don't have at least one cat is 1.0033%

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