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2 years ago

7.857 rounded to the nearest hundredth

Mathematics

1 answer:

garri49 [273]2 years ago

7 0

This answer founded is 7.86 7 is greater than 5 changing it to a 6

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Evaluate the function requested. Write your answer as a fraction in lowest terms. FInd Sin A

castortr0y [4]

Answer: 4 / 5

Reasoning:

1) The function sine is defined as:

sin(x) = opposite-leg / hypotenuse

2) From the figure:

x = A
opposite-leg = 20
hypotenuse = 25

3) Calculations:

sin(A) = 20 / 25 = 4 / 5

Answer: 4 / 5

6 0

2 years ago

Read 2 more answers

Write the equation of the line that passes through (1, 3) and has a slope of 2 in point-slope form. (2 points) y − 1 = 2(x − 3)

NARA [144]

Answer:

y − 3 = 2(x − 1)

Step-by-step explanation:

The point-slope form of the equation of a line with slope m through point (h, k) is ...

y -k = m(x -h)

You have m=2, h=1, k=3, so the equation is ...

y -3 = 2(x -1)

8 0

3 years ago

Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How

HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that $\mu = 5.2r$ , in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

$P(X \geq 1) = 1 - P(X = 0) = 0.99$

Thus:

$P(X = 0) = 1 - 0.99 = 0.01$

We have that:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}$

Then

$e^{-5.2r} = 0.01$

$\ln{e^{-5.2r}} = \ln{0.01}$

$-5.2r = \ln{0.01}$

$r = -\frac{\ln{0.01}}{5.2}$

$r = 0.89$

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

3 0

2 years ago

If 1once of toppings costs. .50 how much would 11onces be

dybincka [34]

Answer:

If one ounce of toppings cost $0.50, then you would need to take $0.50*11

.5*11= 5.5

11 ounces would be $5.50

hope this helps ;)

6 0

2 years ago

WILL GIVE BRAINLIEST!! FINALS!

GenaCL600 [577]

Factor completely x³ + 6x² - 3x – 18
$- 6 + 6( - 6)^{2} - 3( - 6) - 18 \\ - 6 +6 \times 6 ^{2} + 18 - 18 \\ - 6 + 6 ^{3} + 18 - 18 \\ - 6 + 216 \\ 210$
with a root of x = -6

the answer is 210

3 0

2 years ago