A rug is to fit in a room so that a border of even width is left on all four sides.
If the room is 16 feet by 25 feet and the area of the rug is 220 square feet, how wide will the border
:
Let x = the width of the border around the rug
then
(25-2x) by (16-2x) the dimensions of the rug
:
The area equation
(25-2x)*(16-2x) = 220 sq/ft
FOIL
400 - 50x - 32x + 4x^2 = 220
:
Arrange as a quadratic equation
4x^2 - 82x + 400 - 220 = 0
:
4x^2 - 82x + 180 = 0
Simplify, divide by 2
2x^2 - 41x + 90 = 0
Factor
(2x - 5)(x - 18) = 0
Two solutions
2x = 5
x = 2.5 ft
and
x = 18 ft, obviously this not the solution
;
Border will be 2.5 ft
:
:
Check this by finding the dimension of the rug, and then the area
(25 - 2(2.5))*(16 - 2(2.5)) =
(25 - 5) * (16 - 5) =
20 * 11 = 220
About 9 with all the factors repeating but switched around but without any repeating numbers their are about 5
Answer:
f(x)=|1/2x|
Step-by-step explanation:
Answer:
Rearrange the number to make 4n+n+6-2, then add them all up into 5n+4, since n is equal to 1n, you can make 5n by add 4n and n. So the answer is 5n+4
2m+2. Because u subtract 5m with 5m which gives u m then u do the same with 7m then u get 2m,then u subtract 4 from 4 and 6 whoch gives u 2