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Zanzabum
3 years ago
14

What is the solution to the system of equations

Mathematics
2 answers:
uranmaximum [27]3 years ago
8 0
(6, -1)
Where the two lines intersect
Afina-wow [57]3 years ago
3 0

Answer:

(6,-1)

Where the two liner lines intersect

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The price of tomatoes went from $1.12 per pound to $1.96 per pound in 3 years. find the rate of change of the price of tomatoes.
ad-work [718]

\bf \begin{array}{|cc|ll} \cline{1-2} \stackrel{x}{year}&\stackrel{y}{price}\\ \cline{1-2} 0&1.12\\ 3&1.96\\ \cline{1-2} \end{array}~\hspace{10em} (\stackrel{x_1}{0}~,~\stackrel{y_1}{1.12})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{1.96}) \\\\\\ \stackrel{\textit{rate of change}}{slope = m\implies} \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1.96-1.12}{3-0}\implies \cfrac{0.84}{3}\implies 0.28

7 0
3 years ago
The table below contains four statements.
kirill115 [55]

Answer:

Hey your answer is d I used this app called desmos graphing calculator it’s very helpful for graphs. Hope I helped!!

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
12-6r=2r+36 (2-step equations)
mart [117]

Answer: r=-3

Step-by-step explanation:

12-6r=2r+36

12=8r+36

-24=8r

r=-3

5 0
2 years ago
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You are to drive to an interview in another town, at a distance of 270 km on an expressway. The interview is at 11:15 a.m. You p
Yuri [45]

Answer:

the least required speed  is 103.88 km/h

Step-by-step explanation:

Data provided in the question:

Total distance = 270 km

Total time to reach = Time between 8 a.m and 11:15 a.m i.e 3.25 hours

Now,

For the distance of 110 km speed was 100 km/h

therefore, the time taken to cover 110 km = \frac{\textup{Distance}}{\textup{speed}}

= \frac{\textup{110 km}}{\textup{100 km/h}}

= 1.1 hour

For another 43 km speed was 42 km/h

therefore, the time taken to cover 43 km =  \frac{\textup{Distance}}{\textup{speed}}

= \frac{\textup{43 km}}{\textup{42 km/h}}

= 1.0238 hours

Now,

The distance left to be covered = 270 - 110 - 43 = 117 km

Time left = 3.25 h - 1.1 h - 1.0238 h = 1.1262 h

Thus required speed = \frac{\textup{117 km}}{\textup{1.1262 h}}

= 103.88 km/h

Hence, the least required speed  is 103.88 km/h

6 0
3 years ago
Write the polynomial in standard form: x^2+4-3x
Sonbull [250]

Answer:

x^2-3x+4

Step-by-step explanation:

6 0
3 years ago
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