Answer:
H = V0y t - 1/2 g t^2 equation for vertical height of object with initial speed (V0y = V0 sin theta)
If H is to be considered an absolute value from t = 0
h = H + 3 = V0y t - 1/2 g t^2 + 3 where h is height from ground
Answer: Collinear, equidistance, and noncoplanar
Step-by-step explanation:
, (49)^1/2 we can write it as square root of 49 , and also the square root of 49 is 7
So assuming that x2=x^2 and not 2x
3(7+2^2)
3(7+4)
3(11)
33
