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Masteriza [31]
3 years ago
6

given f(x)=3^x-2 and g(x)=f(3x)+4, write the function rule for function g and describe the types of transformations that occur b

etween function f and function g.
Mathematics
1 answer:
Leviafan [203]3 years ago
5 0

Answer:

g(x)=3^{3x}+2

The transformation that occurs from f(x)\rightarrow g(x) is compression by 3 units horizontally and shift  of 4 units upwards.

Step-by-step explanation:

Given

f(x)=3^x-2

g(x)=f(3x)+4

Translation Rules:

f(x)\rightarrow f(cx)

If c>1 the function is compressed c units horizontally.

If c and c>0  the function stretches c units horizontally.

f(x)\rightarrow f(x)+c

If c>0 the function shifts c units to the up.

If c the function shifts c units to the down.

Applying the rules to f(x)

Step 1

f(x)\rightarrow f(3x)

f(3x)=3^{3x}-2

[compressed 3 units horizontally]

Step 2

f(3x)\rightarrow f(3x)+4=g(x)

f(3x)+4=3^{3x}-2+4

∴ g(x)=3^{3x}+2

[shifts 4 nits up]

∴ The transformation that occurs from f(x)\rightarrow g(x) is compression by 3 units horizontally and shift  of 4 units upwards.

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I need help writing a function rule for this set of values. Thanks!
Nonamiya [84]

Answer:

2-1/-2--4= 1/2

0-1/0-2=-1/-2

2-0/-1-0=2/-1

-2--1/4-2=-1/2

can i have a Brainliest plz thank you

3 0
3 years ago
Can you please help me on -5(-4r-6)=5(6-r)
Wewaii [24]

The answer you are looking for is no solution.

To find this, you first distribute the -5 into the parenthesis (-4r - 6). -5 x -4r = 20r and -5 x -6 = 30.Next, distribute the 5 into the parenthesis (6 - r). 5 x 6 = 30 and 5 x r = 5r.

The equation says 20r + 30 = 5r + 30. Now you solve for r.Subtract 5r from both sides. This leaves the equation to say 15r + 30 = 30. Then subtract 30 from both sides, to get 15r = 0.

At this point, since there is a zero on the opposite side of the variable, you can assume it will be no solution, since multiplying or dividing 0 by anything, is 0. However, I'll finish the problem, to show that it is no solution.

Divide 15 from both sides, leaving r = 0, which is no solution.

I hope this helps!

4 0
3 years ago
The sum of 3 consecutive integral numbers is 117. find the numbers.
Anton [14]
An integral number is just a whole number. Consecutive means they are neighbouring in the number line(e.g. 2,3,4). Let the smallest number be x:

x + (x+1) + (x+2) = 3x + 3 = 117

3x = 114

x = 38

Hence the numbers are 38, 39, 40
8 0
3 years ago
A new car dealer offered to sell her demonstrator model for 90% of the retail price. If the sale price was $9,750, what was the
Mariulka [41]

90% = 9,750

9750/90 = 1%

1% = 108.3

100% = 10,833.3

original retail price = $10,833.30

4 0
3 years ago
Dylan has a bank that sorts coins as they are dropped into it. A panel on the front displays the total number of coins inside as
babunello [35]

Answer:

The equations

x + y = 80

0.25x + 0.1y = 16.25

The solution

55 dimes and 25 quarters

Step-by-step explanation:

Given

Let

x \to quarters

y \to dimes

Total = 80

Worth = \$16.25

Required

Set up a system of equation to calculate the number of each coin

The total coin of 80 implies that:

x + y = Total

x + y = 80

A dime = $0.1

A quarter = $0.25

So, the worth of the coin is:

0.25 * x + 0.1 * y = Worth

0.25x + 0.1y = 16.25

So, the equations are:

x + y = 80

0.25x + 0.1y = 16.25

Next, solve for x and y

Multiply the second equation by 4

0.25x + 0.1y = 16.25 by 4

x + 0.4y = 65

Subtract from x + y = 80

x- x + y - 0.4y = 80 - 65

0.6y = 15

Solve for y

y = 25

We have:

x + y = 80

x = 80 - y

x = 80 - 25

x = 55

<em>Hence, there are 55 dimes and 25 quarters</em>

3 0
3 years ago
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