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3 years ago

13

a third of the class has pets 4 of the class have hamsters there are 27 pupils in the class five people in the class have green

eyes how many pupils have pets?

2 answers:

Vaselesa [24]3 years ago

8 0

13 pupils have pets. Green eues was irrelevant

Pani-rosa [81]3 years ago

6 0

9 pupils a third of 27 is 9 green and 4 hamsters are irrelevant.

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Arya and Cody each manage a landscaping business.

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And? Congrats? Please write the full question

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2 years ago

If the volume of the pyramid shown is 360 inches cubed, what is its height?

dimaraw [331]

Answer:

9 inches

Step-by-step explanation:

The formula for the volume of a rectangular pyramid is $V = \frac{1}{3}(l*w*h)$

Here we have volume (V), base (L), and width (W)
V = 360 in³, L = 12 in, W = 10 in

We need to manipulate the volume equation to solve for the height (H)

First we need to multiply both sides by 3 to get rid of the fraction: 3V = L×W×H
Then we need to divide both sides by (L×W) to get: $\frac{3V}{lw} =h$

Now we can plug in the given values:

$\frac{3(360in^{3}) }{(12 in)(10in)} =\frac{1080in^{3} }{120in^{2} } = 9in$
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3 years ago

How do you multiply(2x+3)(x-7)

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Answer:

2x(x-7)+3(x-7)

2x²-14x+3x-21

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3 years ago

Evaluate the following expression when x = -4 and y = 4. x^6-x/4y

tester [92]

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Step-by-step explanation:

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2 years ago

In this exercise, T: R2 → R2 is a function. For each of the following parts, state why T is not linear. (a) T(a1, a2)= (1, a2) (

DENIUS [597]

Answer:

a) T is not homogeneous
b) T is not additive
c) T is not homogeneous
d) T is not additive
e) T is not additive

Step-by-step explanation:

In each case there is an example where one property of linear functions fails.

a) $T(2(1,0))=T((2,0))=(1,0); 2T((1,0))=2(1,0)=(2,0)$ . These vectors are not equal, then T doesn't satisfy the condition of scalar multiplication (homogeneity).

b) $T((1,2)+(2,3))=T(3,5)=(3,9); T((1,2))+T((2,3))=(1,1)+(2,4)=(3,5)$ . Because these vectors are not equal, T doesn't satisfy the property of vector addition (additivity).

c) $T(\frac{1}{2}(\pi,0))=T((\frac{\pi}{2},0))=(\sin(\frac{\pi}{2}),0)=(1,0); \frac{1}{2}T((\pi,0))=\frac{1}{2}(0,0)=(0,0)$ so T is not homogeneous.

d) $T((-1,0)+(1,0))=T(0,0)=(0,0); T((-1,0))+T((1,0))=(1,0)+(1,0)=(2,0)$ then T is not additive.

e) $T((0,0)+(1,0))=T(1,0)=(2,0); T((0,0))+T((1,0))=(1,0)+(2,0)=(3,0)$ then T is not additive.

8 0

3 years ago