How many different groups of students can show up for a seminar with an enrollment of 12 ?

Mathematics

1 answer:

nexus9112 [7]4 years ago

8 0

The solution would be like this for this specific problem:

12! = 12 * 11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1

= 479,001,600

<span>So there are 479,001,600 <span>different group of students that can show up for a seminar with an enrollment of 12.</span></span>

You might be interested in

Please see attachment

Inga [223]

The surface area of a regular tetrahedron with edge length s is

... A = (√3)s²

For your edge length of 4 inches, the surface area is

... A = (√3)(4 in)² = 16√3 in²

8 0

4 years ago

Simplafy them and here you go

Phantasy [73]

Answer:

CLAIMED

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Given the explicit formula an = 125 + 18(n - 1), find the 49th term.

RideAnS [48]

125+ 18( 49-1 )
=125 + 18( 48)
=125 +864
=989
The 49th term is 989

5 0

3 years ago

PLEASE can someone explain why The exact value of sec ( π/6) is 2 /√ 3 ??

Umnica [9.8K]

$\bf sec\left( \frac{\pi }{6} \right)\qquad recall\to sec(\theta)=\cfrac{1}{cos(\theta)}\qquad thus
\\\\
sec\left( \frac{\pi }{6}\right)\iff \cfrac{1}{cos\left( \frac{\pi }{6}\right)}
\\\\\\
\textit{check your Unit Circle for what the }cos\left( \frac{\pi }{6}\right)\ is
\\\\\\
\cfrac{1}{\frac{\sqrt{3}}{2}}\implies \cfrac{\frac{1}{1}}{\frac{\sqrt{3}}{2}}\implies 
\cfrac{1}{1}\cdot \cfrac{2}{\sqrt{3}}\implies \cfrac{2}{\sqrt{3}}$

3 0

3 years ago

Bert collector wants 100 birds in the budget is exactly $100 the bluebird cost $10 the green bird cost three dollars the yellow

Ghella [55]

Answer:

Step-by-20 yellow birds.50=$10.00

6 Bluebirds $10.00= $60.00

10 green birds $10= $30.00

Totaling $100 and more than one of each bird step explanation:

3 0

4 years ago

How many different groups of students can show up for a seminar with an enrollment of 12 ​?

How many different groups of students can show up for a seminar with an enrollment of 12 ?