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Sergio [31]
3 years ago
10

2 2 4 x 8 8 How do you solve it?

Mathematics
1 answer:
Naddik [55]3 years ago
6 0

Answer:

does the x means multiply or its a variable.. and is it really written that way?

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The courtyard behind jennies house is shaped like a trapaziod. The base mesures 8 meters and 15 meters.The height of the trapazo
77julia77 [94]
Formula for trapezoid area is A=b1+b2 x heightx 1/2 so your answer would be 161m squared
7 0
3 years ago
Y-(5-(y-x)) x = 4 y = 6<br><br> I need the steps please, this is a little bit confusing..
KATRIN_1 [288]

Answer:

3

Step-by-step explanation:

substitute x = 4 , y = 6 into the expression

y - (5 - (x - y))

= 6 - (5 - (6 - 4))

= 6 - (5 - 2))

= 6 - 3

= 3

3 0
2 years ago
Which expressions are equivalent to g + h + (j + k)? Check all that apply.
Paha777 [63]

Answer:

3.

{ \tt{g + h + (j + k)}} \\  = (g + h) + j + k

5 0
3 years ago
Read 2 more answers
Please help me out!!!!!
Neko [114]

Given:

The zeros of the polynomial are -2,\pm 5,4.

Degree = 4

Leading coefficient  = 1

To find:

The polynomial.

Solution:

If c is a zero of a polynomial, then (x-c) must be a factor of the polynomial.

Here, -2,4,-5, 5, are zeros of the required polynomial, so (x+2), (x-4), (x+5), (x-5) are factors of required polynomial.

p(x)=(x+2)(x-4)(x+5)(x-5)

p(x)=(x^2-4x+2x-8)(x^2-5^2)     [\because a^2-b^2=(a-b)(a+b)]

p(x)=(x^2-2x-8)(x^2-25)

Using distributive property, we get

p(x)=x^2(x^2-25)-2x(x^2-25)-8(x^2-25)

p(x)=x^4-25x^2-2x^3+50x-8x^2+200

On combining like terms, we get

p(x)=x^4-2x^3+(-25x^2-8x^2)+50x+200

p(x)=x^4-2x^3-33x^2+50x+200

Here, the leading coefficient is 1. So, it is the required polynomial.

Therefore, the correct option is E.

3 0
3 years ago
Cat+Cat+Cat=15
tankabanditka [31]

<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>2</em><em>5</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>.</em>

<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

<em>~</em><em>p</em><em>r</em><em>a</em><em>g</em><em>y</em><em>a</em>

5 0
3 years ago
Read 2 more answers
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