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mr_godi [17]
3 years ago
11

Please help me immediately ​

Mathematics
1 answer:
Elis [28]3 years ago
6 0
I hope this helps you out. It is very tedious

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Help&amp;EXPLAIN <br><br> Don’t use for points or will be reported and I’ll take the points back
ella [17]

Answer:

x = 60°

Step-by-step explanation:

since, the triangles are complementary the sum of their measures will be 90°

now,

  • =》30° + x = 90°

  • =》x = 90° - 30°

  • =》x = 60°
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Which of the following statements is false about most checking accounts?
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If there are 45 guests at the party, predict how many would choose a gift card?
sergij07 [2.7K]

Answer:

Since there is a 50-50 chance of a person at the party choosing a gift card, and since there can only be 1 of 2 outcomes, we can assume that there will either be more people choosing a gift card than not, or there will be more people not choosing a gift card than are. So, that means that there would be 23 people (more or less) choosing a gift card and 22 people (more or less) not choosing a gift card or vice-versa.

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3 years ago
From exterior point L of circle O, tangent segments LP and LQ are drawn such that the measure of angle PLQ is 60 degrees. If a r
GenaCL600 [577]
Refer to the attached diagram for help.

All radii of a circle are congruent.
Tangent segs LP and LQ are congruent. (Tangent segs drawn to a circle from the same point are congruent)

Because of this we can establish OPLQ as a kite.

OPLQ is a kite implies that OL bis. angle PLQ.
An angle bis. divides an angle into 2 congruent, parts, so angle OLP must be 30 degrees.

Since tangents form right angles with the radius, angle OPL is right.

Now we have a right triangle OPL with a 30-degree angle. The other angle must be 60 degrees because of the no-choice theorem. (180-(30+90)) = 60
We know that OP is 6 because it is a radius of circle O. How do we use that to find OL? Well, we <em>could</em> use trig, but you might recognize this as a special triangle!

The side opposite the 30 degree angle = x
The side opposite the right angle = 2x

So OL must be 12!

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