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3 years ago

Cat+Cat+Cat=15

Mathematics

2 answers:

tankabanditka [31]3 years ago

5 0

The right answer is 25.

Look at the attached picture.

Hope it will be helpful to you...

Good luck on your assignment

~pragya

ch4aika [34]3 years ago

3 0

Answer:

Step-by-step explanation:

3x10=30

30-5=25

Brainliest is greatly appreciated

Answered by: Skylar

5/22/2020

12:16 PM (Eastern Time)

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How do you do this? Please help x

kirill115 [55]

Answer:

Step-by-step explanation:

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Table for the input-output values is,

x -1 0 1 2 3

y -7 -4 -1 2 5

Now we can plot these points on the graph (graph attached).

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2 years ago

The perimeter of a rectangular red sticker is 34 mm. it is 8 mm tall. how wide is it?

Orlov [11]

Answer:

9 mm wide

Step-by-step explanation:

Perimeter = length x 2 + width x 2

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3 years ago

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FIND THE GCF. Mathematics

Rom4ik [11]

The G.C.F of the given algebraic expression is; ⁴⁹/₆a xy

<h3>What is the G.C.F (Greatest Common Factor)?</h3>

The greatest common factor (GCF or GCD or HCF) of a set of whole numbers is the largest positive integer that divides evenly into all numbers with zero remainder. For example, for the set of numbers 18, 30 and 42 the GCF = 6.

We are given the algebraic expression;

(3 x y * 4x²y * ¹/₁ * 5x³y ^ z * 4)7a * 1/1 * 7*6

Expanding this further gives;

⁴⁹/₆a((3xy * 4x²y * 20x³y ^ z )

Now, the GCF of the terms inside the bracket would be x y. Thus, expanding the GCF we have;

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Read more about G.C.F at; brainly.com/question/219464

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1 year ago

Find the interquartile range for a data set having the five-number summary: 3.5, 10.4, 16, 21.7, 27.7

vlabodo [156]

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Step-by-step explanation:

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First get the median:

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Then find the median of the first half of data(3.5, 10.4)

(3.5+10.4)/2 = 6.95

Then find the median of the last half of data(21.7, 27.7)

(21.7+27.7)/2 = 24.7

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3 years ago

Brenda collected this data from an experiment.

Gelneren [198K]

Answer:

7.04

Step-by-step explanation:

To get the value of residual of the data point, we simply substitute 11 for t

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3 years ago

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