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Wittaler [7]
3 years ago
8

What is the length of the diagonal for the given rectangular prism to the nearest whole unit?

Mathematics
1 answer:
klemol [59]3 years ago
6 0
Length of the diagonal : D. 12 cm

The space diagonal of a rectangular prism is derived using the following formula:

d = √(l² + w² + h²)

l = 6; w = 5; h = 9
d = √6² + 5² + 9²
d = √36 + 25 + 81
d = √142
d = 11.916 ⇒ 12 cm

slant height of the given pyramid : 

l = slant height
h = height
a = base radius

l = √h² + a²

i'm assuming that the pyramid base is also the base radius
l = √8² + 12²
l = √64 + 144
l = √208
I = 14.42 ⇒ 14cm

in the event that the pyramid base is not the radius, then 12/2; 6cm
l = √8² + 6²
l = √64 + 36
l = √100
l = 10 cm
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<u>Step-by-step explanation:</u>

Inequalities are the relationships between two expressions which are not equal to one another. The symbols used for inequalities are <, >, ≤, ≥ and ≠.

7 \textgreater x reads as '7 is greater than x' (or ' x is less than 7', reading from right to left).

x \leq -4 reads as ' x is less than or equal to -4' (or '-4 is greater than or equal to x', reading from right to left).

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Here , we have

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3 years ago
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Gekata [30.6K]

Answer:

False. See te explanation an counter example below.

Step-by-step explanation:

For this case we need to find:

P(X_{n+1} = | X_n =i, X_{n-1}=i') =P(X_{n+1}=j |X_n =i) for all i,i',j and for X_n in the Markov Chain assumed. If we proof this then we have a Markov Chain

For example if we assume that j=2, i=1, i'=0 then we have this:

P(X_{n+1} = | X_n =i, X_{n-1}=i') =\frac{1}{2}

Because we can only have j=2, i=1, i'=0 if we have this:

Y_{n+1}=1 , Y_n= 1, Y_{n-1}=0, Y_{n-2}=0, from definition given X_n = Y_n + Y_{n-1}

With i=1, i'=0 we have that Y_n =1 , Y_{n-1}=0, Y_{n-2}=0

So based on these conditions Y_{n+1} would be 1 with probability 1/2 from the definition.

If we find a counter example when the probability is not satisfied we can proof that we don't have a Markov Chain.

Let's assume that j=2, i=1, i'=2 for this case in order to satisfy the definition then Y_n =0, Y_{n-1}=1, Y_{n-2}=1

But on this case that means X_{n+1}\neq 2 and on this case the probability P(X_{n+1}=j| X_n =i, X_{n-1}=i')= 0, so we have a counter example and we have that:

P(X_{n+1} =j| X_n =i, X_{n-1}=i') \neq P(X_{n+1} =j | X_n =i) for all i,i', j so then we can conclude that we don't have a Markov chain for this case.

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Joanne buys a car for $1500 after 12 months Joanne is forced to sell the car for 10% less than what she brought it for, how much
MAVERICK [17]

Answer:

$1350

Step-by-step explanation:

Given she sold the car 10% less than what she bought it, amount she sold the car will be 10% of the amount she bought the car subtracted from the amount she bought he car .

She bought the car for $1500

Therefore,

10% of $1500

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$150

Now , amount she sold the car = $1500 - $150

= $1350

She sold the car for $1350

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