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Lady bird [3.3K]
3 years ago
9

Which graph shows a line with the same y intercept as the graph of 10x - 16y = 40

Mathematics
1 answer:
Amanda [17]3 years ago
4 0

Answer:

The graph option where the y-axis is intercepted at y = -2.5 by the line of the graph.

Step-by-step explanation:

The answer choices for the possible graphs that have the same y-intercept as the graph of 10x - 16y = 40 is missing here.

However, the answer can still be explained here.

We can figure out how the graph would look like.

First, understand that the y-intercept of a graph is the value of y, of the point where the line intercepts the y-axis.

Let's figure out what the y-intercept is given a graph represented by the equation, 10x - 16y = 40.

Rewrite the equation in slope-intercept form.

10x - 16y = 40

-16y = -10x + 40

y = -10x/-16 + 40/-16

y = ⅝x - ⁵/2

Therefore, the y-intercept of the graph of 10x - 16y = 40 is -⁵/2 or -2.5.

✅The graph shows a line with the same y-intercept as the graph of 10x - 16y = 40, would have it's y-axis intercepted at y = -2.5.

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Carlos deposited $7,924 into a savings account 30 years ago. The account has an interest rate of 4.6% and the balance is current
exis [7]

Answer:

n = 1, this means the interest compounds ANNUALLY.

Step-by-step explanation:

Carlos deposited $7,924 into a savings account 30 years ago. The account has an interest rate of 4.6% and the balance is currently $30,541.83. How often does the interest compound?

Compound Interest Formula

: A = P(1 + r/n)^nt

A = Amount after time t

P = Principal (Initial Amount Invested)

r = Interest rate

n = Number of times the interest is compounded

t = time in years

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r = 4.6% = 0.046

t = 30

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Hence,

$30,541.83 = $7924(1 + 0.046/n)^30n

Divide both sides by 7924

$30,541.93/$7924 = (1 + 0.046/n)^30n

$30,541.93/$7924 = (n + 0.046/n)^30n

3.8543576477 = (n + 0.046/n)^30n

We take the logarithm of both sides

log 3.8543576477 = log (n + 0.046/n)^30n

Solving for n,

n = 1

Therefore, from the calculation above, since n = 1, this means the interest compounds ANNUALLY.

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