I took five years before and it was hard for me to remember the postualates. I found it helpful to practice proving problems that involved the postualate. Some postualates like SAS are just abbreviations. SAS- Side-Angle-Side
Try breaking these into sections.
Twice: 2 times
The sum of: add
A number: choose a variable, like x
---Thus "the sum of a number and 4" becomes "add x and 4" which, mathematically, is "x+4"
-----Continuing to put it all together, "Twice the sum of a number and four" becomes "2 times (x+4)" which, mathematically, is "2(x+4)"
Is: equals
-------"Twice the sum of a number and four is" becomes "2(x+4)="
23 less than: subtract 23. This one tends to trick people; "23 less than" will become "__ - 23", NOT "23 - __"
three times the number: 3 times x
---"23 less than three times the number" becomes "subtract 23 from 3 times x" which, mathematically, is "3x-23"
-------So the final phrase: 2(x+4)=3x-23"
Answer:
segment AB over segment A double prime B double prime = the square root of 13 over 2 times the square root of 13
Step-by-step explanation:
Triangle ABC has vertices at points A(-3,3), B(1,-3) and C(-3,-3).
1. Reflection over x = 1 maps vertices A, B and C as follows
- A(-3,3)→A'(5,3);
- B(1,-3)→B'(1,3);
- C(-3,-3)→C'(5,-3).
2. Dilation by a scale factor of 2 from the origin has the rule
(x,y)→(2x,2y)
So,
- A'(5,3)→A''(10,6);
- B'(1,3)→B''(2,6);
- C'(5,-3)→C''(10,-6)
See attached diagram for details
Note that
![A''B''=2AB\\ \\A''C''=2AC\\ \\B''C''=2BC,\\ \\AB=\sqrt{(-3-1)^2+(3-(-3))^2}=\sqrt{16+36}=\sqrt{52}=2\sqrt{13}](https://tex.z-dn.net/?f=A%27%27B%27%27%3D2AB%5C%5C%20%5C%5CA%27%27C%27%27%3D2AC%5C%5C%20%5C%5CB%27%27C%27%27%3D2BC%2C%5C%5C%20%5C%5CAB%3D%5Csqrt%7B%28-3-1%29%5E2%2B%283-%28-3%29%29%5E2%7D%3D%5Csqrt%7B16%2B36%7D%3D%5Csqrt%7B52%7D%3D2%5Csqrt%7B13%7D)
so
![\dfrac{AB}{A''B''}=\dfrac{2\sqrt{13}}{2\cdot 2\sqrt{13}}=\dfrac{\sqrt{13}}{2\sqrt{13}}](https://tex.z-dn.net/?f=%5Cdfrac%7BAB%7D%7BA%27%27B%27%27%7D%3D%5Cdfrac%7B2%5Csqrt%7B13%7D%7D%7B2%5Ccdot%202%5Csqrt%7B13%7D%7D%3D%5Cdfrac%7B%5Csqrt%7B13%7D%7D%7B2%5Csqrt%7B13%7D%7D)
Answer:
I'm pretty sure that the answer would be 229/236.
Step-by-step explanation:
Ok so. Since the results of the test is 229 for a girl and the results for a boy is 7. So i'm pretty sure what to do is combine both the results and keep that as the denominator. And then the numerator will be the result. So in this case the numerator would be 229 and the denominator would be 236.
I hope this helped, have a great day!!!