The point (9, 12) is on the terminal side of an angle in standard position.

I need help, urgently.

Korvikt [17]

Answer:

y = -0.5(x - 4)^2 + 5.

y = -0.5x^2 + 4x - 3.

Step-by-step explanation:

The vertex is at (4, 5). so we have:

f(x) = a(x - 4)^2 + 5

When x = 0 y = -3 so substituting in the above:

- 3 = a(0-4)^2 + 5

-8 = 16a

a = -0.5.

So the vertex form is y = -0.5(x - 4)^2 + 5.

Standard form:

y = -0.5(x^2 - 8x + 16) + 5

y = -0.5x^2 + 4x - 8 + 5

y = -0.5x^2 + 4x - 3.

5 0

3 years ago

is finding the perimeter of a figure with all sides of equal length easier tgan finding the perimeter of other figures?

Lelu [443]

Answer:

yes, there are fewer numbers to compute.

It's just one length x the number of sides.

Step-by-step explanation:

6 0

3 years ago

PLEEEEAAAASSSSEEEEEE HELP ME!!!!!!

Lina20 [59]

12 + 8 = 20 Omar has 20 points now

3 0

3 years ago

Read 2 more answers

The operations manager of a manufacturer of television remote controls wants to determine which batteries last the longest in hi

Margarita [4]

Answer:

$t=\frac{107.75-116.75}{\sqrt{\frac{2.75^2}{4}+\frac{9.604^2}{4}}}}=-1.802$

The degrees of freedom are given by:

$df=n_{1}+n_{2}-2=4+4-2=6$

The p value for this case would be given by:

$p_v =2*P(t_{(6)}$

Since the p value is higher than the significance level we have enough evidence to FAIl to reject the null hypothesis and we can conclude that the true mean is not significantly different between the two types of battery

Step-by-step explanation:

Information given

Battery 1 106 111 109 105

Battery 2 125 103 121 118

We can calculate the mean and the deviation with the following formulas"

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_{1}=107.75$ represent the mean for the Battery 1

$\bar X_{2}=116.75$ represent the mean for the Bettery 2

$s_{1}=2.75$ represent the sample standard deviation for the Battery 1

$s_{2}=9.604$ represent the sample standard deviation for the battery 2

$n_{1}=4$ sample size selected for the Battery 1

$n_{2}=4$ sample size selected for the Battery 2

$\alpha=0.1$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to check if the difference in longevity between the two batteries, the system of hypothesis would be:

Null hypothesis: $\mu_{1} = \mu_{2}$

Alternative hypothesis: $\mu_{1} \neq \mu_{2}$

The statistic is given by:

$t=\frac{\bar X_{s1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

The statistic is given by:

$t=\frac{107.75-116.75}{\sqrt{\frac{2.75^2}{4}+\frac{9.604^2}{4}}}}=-1.802$

The degrees of freedom are given by:

$df=n_{1}+n_{2}-2=4+4-2=6$

The p value for this case would be given by:

$p_v =2*P(t_{(6)}$

Since the p value is higher than the significance level we have enough evidence to FAIl to reject the null hypothesis and we can conclude that the true mean is not significantly different between the two types of battery

8 0

3 years ago

Sarah received $55 for her birthday. She used some of that money to buy 3 shirts priced at m dollars each.

Phoenix [80]

There is not enough information so this equation is an unsolvable.
You could figure out the equation if the 3 were M and M had a number but this is unsolvable. SORRY

4 0

3 years ago

Read 2 more answers