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3 years ago

I need help, urgently.

Mathematics

1 answer:

Korvikt [17]3 years ago

5 0

Answer:

y = -0.5(x - 4)^2 + 5.

y = -0.5x^2 + 4x - 3.

Step-by-step explanation:

The vertex is at (4, 5). so we have:

f(x) = a(x - 4)^2 + 5

When x = 0 y = -3 so substituting in the above:

- 3 = a(0-4)^2 + 5

-8 = 16a

a = -0.5.

So the vertex form is y = -0.5(x - 4)^2 + 5.

Standard form:

y = -0.5(x^2 - 8x + 16) + 5

y = -0.5x^2 + 4x - 8 + 5

y = -0.5x^2 + 4x - 3.

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andrezito [222]

Answer:

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Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Given: ABCD is a ∥-gram, BF ⊥ CD , BE ⊥ AD, Prove: △ABE∼△CBF

drek231 [11]

Answer:

Hence proved △ABE∼△CBF.

Step-by-step explanation:

Given,

ABCD is a parallelogram.

BF ⊥ CD and

BE ⊥ AD

To Prove : △ABE∼△CBF

We have drawn the diagram for your reference.

Proof:

Since ABCD is a parallelogram,

So according to the property of parallelogram opposite angles are equal in measure.

$\therefore m\angle A = m\angle B$ ⇒1

And given that BF ⊥ CD and BE ⊥ AD.

So we can say that;

$m\angle F=m\angle E=90\°$ ⇒2

Now In △ABE and △CBF

∠A = ∠C (from 1)

∠E = ∠F (from 2)

So by A.A. similarity postulate;

△ABE∼△CBF

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3 years ago

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3 years ago

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3 years ago