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QveST [7]
4 years ago
12

Solve a(x − b) − 2k = L for x.

Mathematics
1 answer:
erik [133]4 years ago
7 0
a(x-b) -2k = L \\ ax - ab - 2k = L \\ ax = L + ab + 2k \\ x =  \frac{L}{a} + b + 2  \frac{k}{a}
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Answer:

the second one 9v+36

Step-by-step explanation:

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3 0
2 years ago
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Choose all of the equivalent expressions of (a + b)(x + y).
lara31 [8.8K]

Answer:

(a + b)x + (a + b)y

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3 years ago
Suppose 45% of the population has a college degree.
levacccp [35]

Using the normal distribution, there is a 0.2076 = 20.76% probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}, as long as np \geq 10 and n(1 - p) \geq 10.

The proportion estimate and the sample size are given as follows:

p = 0.45, n = 437.

Hence the mean and the standard error are:

  • \mu = p = 0.45
  • s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.45(0.55)}{437}} = 0.0238

The probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3% is <u>2 multiplied by the p-value of Z when X = 0.45 - 0.03 = 0.42</u>.

Hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem:

Z = \frac{X - \mu}{s}

Z = (0.42 - 0.45)/0.0238

Z = -1.26

Z = -1.26 has a p-value of 0.1038.

2 x 0.1038 = 0.2076.

0.2076 = 20.76% probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3%.

More can be learned about the normal distribution at brainly.com/question/28159597

#SPJ1

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Step-by-step explanation:

I hope this is ur required answer

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Answer:

Step-by-step explanation:

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