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Elan Coil [88]
2 years ago
15

What is the number if 5 is added to its twice the sum will be 25?​

Mathematics
2 answers:
saul85 [17]2 years ago
5 0

Answer: 10 & 15

Step-by-step explanation: it's impossible for it to be the same number because it has to be added by five so 5+5=10 and 5+5+5=15 if that's not the answer then I don't know what is I do hope this helps you. 15+ 10=25 so ya.

grigory [225]2 years ago
4 0

Answer:

yes !!!!!! corret

Step-by-step explanation:

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The ratio of teachers to students on a field trip to New York City is 2 to 9. If there are 243 students on the trip,
Veseljchak [2.6K]

Answer:

54 teachers

Step-by-step explanation:

Step one:

given data

The ratio of teachers to students on a field trip to New York City is 2 to 9.

That is the ratio is 2:9

We are told that there are 243 students

Required

We want to find the number of teachers

Step two:

Applying the part to part method we have

let the number of teachers be x

2/9= x/243

cross multiply we have

9x= 243*2

9x= 486

divide both sides by 9

x= 54

Hence there are 54 teachers

4 0
3 years ago
Find - 36<br> .<br> Ο +6<br> -6<br> 9Ο<br> Ο 18
Alinara [238K]

Answer:

+or-6

Step-by-step explanation:

This is a trick question. The answer would be the first choice since you're multiplying -6 by +or-6, meaning that it could still end up as a negative or a positive.

3 0
2 years ago
Read 2 more answers
Determine the density of the rock using correct significant digits. The mass of the rock is 25.69 g.
Dvinal [7]
Density = mass / volume

Mass = 25.69g and Volume = 10 mL

D = 25.69g / 10mL 

Density = 2.569 g/mL
5 0
3 years ago
5. Adam drives his car with an average velocity of 85 km/h eastward. How long will it take him to drive
NISA [10]

Answer:

x = 6.59 hrs = about 6 hours, 35 minutes

Step-by-step explanation:

Adam drives at 85 km / h. Let's set up equivalent fractions to see how long if he drives 560 km.

\frac{85 km}{1  hr} = \frac{560 km}{x hr}

Cross-multiply:

85x = 560

Solve for x:

560/85 = x

<u>x = 6.59 hrs = about 6 hours, 35 minutes</u>

7 0
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A ball with mass m kg is thrown upward with initial velocity 28 m/s from the roof of a building 17 m high. Neglect air resistanc
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a. At its maximum height, the ball has zero vertical velocity, so

-\left(28\dfrac{\rm m}{\rm s}\right)^2=2(-g)(y_{\rm max}-17\,\mathrm m)

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b. The ball's height in the air y at time t is given according to

y=17\,\mathrm m+\left(28\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2

Solve for t when y=0:

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3 0
3 years ago
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