Question

Can someone help me with number 15

Answer 1

Answer:

Step-by-step explanation:

We will evaluate that with n values starting at 1 and ending at 5.  To do that, simply replace the exponent n with 1, then 2, then 3, then 4, then 5.

$f(1)=(\frac{2}{3})^1$  so

$f(1)=\frac{2}{3}$

Then f(2):

$f(2)=(\frac{2}{3})^2$ simplifies a bit so maybe it's easier to see how to handle this:

$f(2)=(\frac{2^2}{3^2})$ so

$f(2)=\frac{4}{9}$

Then f(3):

$f(3)=(\frac{2^3}{3^3})=\frac{8}{27}$

And f(4):

$f(4)=(\frac{2^4}{3^4})=\frac{16}{81}$

And finally, f(5):

$f(5)=(\frac{2^5}{3^5})=\frac{32}{243}$