Please help me on this one please

LenaWriter [7]

17.46% of 126 is 22

Divide 22 by 126:
$22 \div 126 = 0.1746$

Change the decimal into a percentage by multiplying the decimal by 100:
$0.1746 \times 100 = 17.46$

6 0

3 years ago

Read 2 more answers

A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of

Eva8 [605]

Answer:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=250000$ represent the sample mean

$s=37500$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =210250$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:

Null hypothesis: $\mu \leq 210250$

Alternative hypothesis: $\mu > 210250$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

Conclusion

Since is a one right tailed test the p value would be:

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

6 0

3 years ago

Alexa is ordering a taxi from an online taxi service. The taxi charges $4 just for the pickup and then an additional $1.25 per m

Rufina [12.5K]

Answer:

Alex's ride is $15.25

The equation to find this is

1.25m + 4 = cost

m = miles traveled

6 0

2 years ago

a circular racecar track has a radius ig 1.6 miles.about how many times must a car drive around the race track to drive 15 miles

madam [21]

He has to drive around the track about 1.5 times.

We first find the circumference:

C = 2πr = 2(3.14)(1.6) = 10.048

We now divide 15 by this:
15/10.048 ≈ 1.5

8 0

3 years ago

Simplify (6a4b-2c)(-a2bc5)

Soloha48 [4]

It simplifies to -6a^6b^2c^5+2a^2bc^6

4 0

3 years ago