Question

If (x+2) is a factor of 3x^2-4kx-4k^2, then find the value(s) of k

Answer 1

Answer:

The values of k will be:

$k=-1,\:k=3$

Step-by-step explanation:

Let the expression of polynomial P be

$P\left(x\right)=3x^2-4kx-4k^2$

Let the expression if the polynomial Q be

$\:Q\left(x\right)=\:\left(x+2\right)\:$

Plug in Q(x) = 0

0 = x+2

x = -2

As (x+2) is a factor of 3x²-4kx-4k²

substitute x = -2 in the the polynomial

3x²-4kx-4k² = 0

$3\left(-2\right)^2-4k\left(-2\right)-4k^2\:=0$

$12+8k-4k^2=0$

Write in the standard form ax²+bx+c = 0

$-4k^2+8k+12=0$

Factor out common term -4

$-4\left(k^2-2k-3\right)=0$

Factor k²-2k-3: (k+1)(k-3)

$-4\left(k+1\right)\left(k-3\right)=0$

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

$k+1=0\quad \mathrm{or}\quad \:k-3=0$

solving k+1=0

k+1 = 0

k = -1

solving k-3=0

k-3=0

k = 3

Thus, the values of k will be:

$k=-1,\:k=3$