2 years ago

Helps please the question is what was the battery change level when it started charging?

1 answer:

Ket [755]2 years ago

6 0

Answer:

tor buni ami kaitam chai tor bunir aga boro boro 2 ta ami kaitam chai

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Irina-Kira [14]

<span>the product of one term of a multiplicand and one term of its multiplier.</span>

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3 years ago

ser-zykov [4K]

Answer:

Step-by-step explanation:

You;ll run into this formula a lot. Make sure you study it carefully.

A = 25

a = 5

d = 13

Find n

25 = 5 + 13*(n- 1)

20 = 13(n - 1)

This isn't going to work out. 20/13 does not give a whole number which it should.

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3 years ago

Blizzard [7]

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3 years ago

Kitty [74]

Answer:

$-\frac{3p^8}{4q^3}$

Step-by-step explanation:

$\frac{15p^{-4}q^{-6}}{-20p^{-12}q^{-3}}$ can be broken down into three fractions, coefficients, powers of p, powers of q.

$-\frac{15}{20}\cdot\frac{p^{-4}}{p^{-12}}\cdot\frac{q^{-6}}{q^{-3}}$

Simplify the first fraction, then simplify the others by subtracting numerator exponents minus denominator exponents.

$-\frac{3}{4} p^{-4-(-12)} q^{-6-(-3)} =-\frac{3}{4} p^8 q^{-3} = \alpha -\frac{3p^8}{4q^3}$

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2 years ago

11111nata11111 [884]

The answer for the value of 0 is 0=1

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2 years ago