Answer:
The program to this question as follows:
Program:
//header file iostream
#include<iostream> //including file for use basic function
//using name space
using namespace std;
//main method
int main() //defining main method
{
int a[3][3]; //defining two dimension array
int x,y,sum=0; //defining variables
cout<<"Enter array elements: "<<endl; //message
for(x=0;x<3;x++) // for row
{
for(y=0;y<3;y++) //for column
{
cin>>a[x][y]; //input values from user.
}
}
//loop for calculting sum.
for(x=0;x<3;x++)
{
for(y=0;y<3;y++)
{
sum=sum+a[x][y];//add all elements
}
}
cout<<"Sum: "<<sum; //print sum.
return 0;
}
Output:
Enter array elements:
1
2
3
4
5
6
7
8
9
Sum: 45
Explanation:
In the above C++ programming language code first, a header file is included then the main method is declared, inside a main method 2D array that is "a[][]", and an integer variable is defined that are "i, j, and sum". In the next line for loop is used, this loop is used two times that can be described as follows:
- The first time it is used for inserting elements from user ends.
- The second time, it uses the sum variable to add all array elements. and in the last print function that is "cout" is used for print sum variable value.
Answer:
1G
Explanation:
1 'G' as in first generation.
Hope this helped. :)
Answer:
p(x,n)
1. if(n==0) [if power is 0]
2. then result =1.
3.else
4. { result=1.
5. for i=1 to n.
6. { result = result * x. } [each time we multiply x once]
7. return result.
8. }
Let's count p(3,3)
3
0, so come to else part.
i=1: result = result *3 = 3
i=2: result = result *3 = 9
i=2: result = result *3 = 27
Explanation:
here the for loop at step 4 takes O(n) time and other steps take constant time. So overall time complexity = O(n)
Answer:
13:a. 15:c. 14:Unknown answer
Answer: Having the ability to change the source code to fit your needs
Explanation:
