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Anestetic [448]
3 years ago
10

Narrate an incident from the experience of a 14 year old girl which brings out the message: " Never leave till tomorrow what you

can do today."​
Computers and Technology
1 answer:
pogonyaev3 years ago
7 0
Smth called google turbo record United in
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The mathematical constant Pi is an irrational number with value approximately 3.1415928... The precise value of this constant ca
tatiyna

Answer:

I am writing a Python program:

def approxPIsquared(error):

   previous = 8

   new_sum =0

   num = 3

   while (True):

       new_sum = (previous + (8 / (num ** 2)))

       if (new_sum - previous <= error):

           return new_sum

       previous = new_sum

       num+=2    

print(approxPIsquared(0.0001))

Explanation:

I will explain the above function line by line.

def approxPIsquared(error):  

This is the function definition of approxPlsSquared() method that takes error as its parameter and approximates constant Pi to within error.

previous = 8     new_sum =0      num = 3

These are variables. According to this formula:

Pi^2 = 8+8/3^2+8/5^2+8/7^2+8/9^2+...

Value of previous is set to 8 as the first value in the above formula is 8. previous holds the value of the previous sum when the sum is taken term by term. Value of new_sum is initialized to 0 because this variable holds the new value of the sum term by term. num is set to 3 to set the number in the denominator. If you see the 2nd term in above formula 8/3^2, here num = 3. At every iteration this value is incremented by 2 to add 2 to the denominator number just as the above formula has 5, 7 and 9 in denominator.

while (True):  This while loop keeps repeating itself and calculates the sum of the series term by term, until the difference between the value of new_sum and the previous is less than error. (error value is specified as input).

new_sum = (previous + (8 / (num ** 2)))  This statement represents the above given formula. The result of the sum is stored in new_sum at every iteration. Here ** represents num to the power 2 or you can say square of value of num.

if (new_sum - previous <= error):  This if condition checks if the difference between the new and previous sum is less than error. If this condition evaluates to true then the value of new_sum is returned. Otherwise continue computing the, sum term by term.

return new_sum  returns the value of new_sum when above IF condition evaluates to true

previous = new_sum  This statement sets the computed value of new_sum to the previous.

For example if the value of error is 0.0001 and  previous= 8 and new_sum contains the sum of a new term i.e. the sum of 8+8/3^2 = 8.88888... Then IF condition checks if the

new_sum-previous <= error

8.888888 - 8 = 0.8888888

This statement does not evaluate to true because 0.8888888... is not less than or equal to 0.0001

So return new_sum statement will not execute.

previous = new_sum statement executes and now value of precious becomes 8.888888...

Next   num+=2  statement executes which adds 2 to the value of num. The value of num was 3 and now it becomes 3+2 = 5.

After this while loop execute again computing the sum of next term using       new_sum = (previous + (8 / (num ** 2)))  

new_sum = 8.888888.. + (8/(5**2)))

This process goes on until the difference between the new_sum and the previous is less than error.

screenshot of the program and its output is attached.

6 0
3 years ago
I keep getting this error: postfix.cpp: In function ‘double RPN_evaluation(std::string)’: postfix.cpp:42:26: error: cannot conve
Svetradugi [14.3K]

Answer:

expr.at(g) returns a string, not a char. They are not the same thing and that is what the compiler is complaining about.

3 0
3 years ago
URGENT!
lutik1710 [3]

<u>Explanation:</u>

Hey there! you need not to panic about it ,your program didn't have Driver program i.e main program! the correct & working code is given below:

// C++ program to count  even digits  in a given number .

#include <iostream>  

using namespace std;  

// Function to count digits

int countEven(int n)  

{  

int even_count = 0;    

while (n > 0)  

{  

 int rem = n % 10;  

 if (rem % 2 == 0)  

  even_count++;  

 n = n / 10;  

}  

cout << "Even count : "

 << even_count;  

if (even_count % 2 == 0 )  

 return 1;  

else

 return 0;  

}  

// Driver Code  

int main()  

{  

int n;  

std::cin >>n;

int t = countEven(n);  

return 0;  

}  

6 0
3 years ago
Have you searched Buzz Ch.at on playstore​
deff fn [24]

Answer:

Reorder terms.

y=52x−1

Cancel the common factor of 22.Factor 22 out of −2-2.

y−4=5x2+52⋅(2(−1))y-4=5x2+52⋅(2(-1))

Cancel the common factor.

y−4=5x2+52⋅(2⋅−1)y-4=5x2+52⋅(2⋅-1)

Rewrite the expression.

y−4=5x2+5⋅−1y-4=5x2+5⋅-1

Multiply 55 by −1-1.

y−4=5x2−5

3 0
3 years ago
Plsss help me<br>give two examples of problems that can occur when sytems do not work properly​
melomori [17]

Answer:

Explanation:

1. There can be a run out of something ex. The water cycle we could run out of water if evaporation stops happening

2. Something wont happen ex. In a shoe factory if no one is boxing the shoes the shoes don’t get boxed.

Hope this helps

6 0
3 years ago
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