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Nostrana [21]
2 years ago
11

How do you do this problem 2/5+4a=-6/5 what does A = to?

Mathematics
1 answer:
a_sh-v [17]2 years ago
4 0

Answer: A = -2/5

Step-by-step explanation:

- 6/5 - 2/5 = - 8/5 aka - 1 3/5

-1 3/5 ÷ 4 = - 2/5

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Yao's Asian Market sells dragon fruit for $3 each. The store usually sells 20 dragon fruits a week. Dragon fruit is in season, a
exis [7]
The quantity demanded would increase due to the cheaper price people would want to take advantage and buy it when it was on sale. There is not enough information to determine whether the supply or demand would maintain so D is your answer.

4 0
3 years ago
Brownies are now on sale. Each brownie costs $0.20 less than the original price. Right now, if you buy 8 of them it will cost $1
Airida [17]

Answer: The original price of brownie was $2.1 each.

Step-by-step explanation:

since we have given that

Let the original price will be x

Number of brownie purchased = 8

According to question , each brownie costs $0.20 less than the original price.

So, it becomes

8\times (x-0.20)=\$15.20\\\\8x-1.6=15.20\\\\8x=15.20+1.60\\\\8x=16.8\\\\x=\frac{16.8}{8}\\\\x=\$2.1

Hence, the original price of brownie was $2.1 each.

5 0
3 years ago
HURRY FROM ODDESYWARE
antoniya [11.8K]
It should be the last one but sorry if i’m wrong
6 0
3 years ago
A random sample of 102 full-grown lobsters had a mean weight of 16 ounces and a standard deviation of 3.4 ounces. Construct a 98
pshichka [43]

Answer:

The best point estimate for a confidence interval estimating the population μ is 16 ounces.

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The best point estimate for a confidence interval estimating the population μ is

The sample mean, so 16 ounces.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 102 - 1 = 101

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 101 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 2.36

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.36\frac{3.4}{\sqrt{102}} = 0.79

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 16 - 0.79 = 15.21 ounces

The upper end of the interval is the sample mean added to M. So it is 16 + 0.79 = 16.79 ounces

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

4 0
2 years ago
Given f(x) = x^2-3 and g(x)=x+2/x. Find (g°f)(4)
goblinko [34]

Answer:

15/13

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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