Hi there, your question was incomplete, so I will be solving a similar question so it would help you to understand how to answer these types of questions
Q) A chemist must dilute 22.5mL of 119μ M aqueous silver(II) oxide AgO solution until the concentration falls to 65.0μ M . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Round your answer to significant digits.
Answer:
<u>Final Volume V2 = 41.2 mL</u>
Explanation:
We will start by first recalling the formula of dilution which goes by,
M1 * V1 = M2 * V2 ------------------------------(1)
Now let us consider V1 = 22.5 mL
M1 = 119μ M
M2 = 65.0μ M
lets substitute the values above in equation 1,
M1 * V1 = M2 * V2
V2 = (M1 * V1)/M2 ( I have created V2 as the subject here)
V2 = (119*22.5)/65
<u>V2 = 41.2 mL</u>
Answer:
1.4×10⁵ N
Explanation:
Find the acceleration.
Given:
v₀ = -1000 m/s
v = 0 m/s
t = 120 s
Find: a
v = at + v₀
(0 m/s) = a (120 s) + (-1000 m/s)
a = 8.33 m/s²
Find the force.
∑F = ma
F − mg = ma
F = mg + ma
F = m (g + a)
F = (75600 / 9.8) (9.8 + 8.33)
F = 1.4×10⁵ N
The answer is when GAS IS BURNED because when gas is burned, it cannot return into its previous state. Also, new substances are formed.
Answer:
The change of the volume of the device during this cooling is
Explanation:
Given that,
Mass of oxygen = 10 g
Pressure = 20 kPa
Initial temperature = 110°C
Final temperature = 0°C
We need to calculate the change of the volume of the device during this cooling
Using formula of change volume
Put the value into the formula
Hence, The change of the volume of the device during this cooling is
Answer:
Depending on the tempetures he's most likly looking to see what temp it will grow under and which one grows the fastest
Explanation: