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Harman [31]
3 years ago
15

player A led a baseball league in runs batted in for the 2006 regular season. player B. who came in second player to A, had 13 f

ewer runs batted in for the 2006 regular season. together, these two players brought home 250 runs during the regular 2006 regular season. how many runs batted in did the player A and B each account for?
Mathematics
1 answer:
Alla [95]3 years ago
7 0
A= player A runs batted in
b= player B runs batted in= a-13

250= a + b
substitute b= a-13 for b

250= a + (a-13)
combine like terms
250= 2a -13
add 13 to both sides
263= 2a
divide both sides by 2
131.5= a

Substitute a= 131.5 into equation
250= a + b
250= 131.5 + b
subtract 131.5 from both sides
118.5= b

Hope this helps! :)
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3 years ago
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Identify each function as a constant, direct variation, absolute value, or greatest integer function.
Anton [14]
None of those describe this function.

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It doesn't show direct variation, because it can't be represented in the form
y = kx.

It isn't an absolute value function because the absolute value isn't taken anywhere.
If it was an absolute value function it would look something like this:
g(x) = |x+3|

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If it was a greatest integer function it would look something like this:
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Are you sure you typed that question right?
7 0
3 years ago
Six by the power of 2×3
Sergio039 [100]

Answer:

46,656

Step-by-step explanation:

6^2x3=

6^6=

6x6x6x6x6x6=

46,656

Hope that helps!

5 0
2 years ago
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Please answer I am begging !!!
dlinn [17]

Answer:

z=8,154

Step-by-step explanation:

To find the answer for this is you take 21,137 and subtract 12,983 from it.

21,137-12,983=8,154

12,983 + z = 21,137

12,983 + 8,154 = 21,137

3 0
3 years ago
You are asked to do a study of shelters for abused and battered women to determine the necessary capacity in your city to provid
ohaa [14]

Answer:

Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.

274 shelters will be needed.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 250, \sigma = 75

If the city’s shelters have a capacity of 350, will that be enough places for abused women on 95% of all nights?

What is the percentile of 350?

This is the pvalue of Z when X = 350.

Z = \frac{X - \mu}{\sigma}

Z = \frac{250 - 150}{75}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082.

Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.

If not, what number of shelter openings will be needed?

The 95th percentile, which is X when Z = 1.645. So

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 150}{75}

X - 150 = 1.645*75

X = 274

274 shelters will be needed.

5 0
2 years ago
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