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Harman [31]
3 years ago
15

player A led a baseball league in runs batted in for the 2006 regular season. player B. who came in second player to A, had 13 f

ewer runs batted in for the 2006 regular season. together, these two players brought home 250 runs during the regular 2006 regular season. how many runs batted in did the player A and B each account for?
Mathematics
1 answer:
Alla [95]3 years ago
7 0
A= player A runs batted in
b= player B runs batted in= a-13

250= a + b
substitute b= a-13 for b

250= a + (a-13)
combine like terms
250= 2a -13
add 13 to both sides
263= 2a
divide both sides by 2
131.5= a

Substitute a= 131.5 into equation
250= a + b
250= 131.5 + b
subtract 131.5 from both sides
118.5= b

Hope this helps! :)
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Step-by-step explanation:

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2 years ago
A culture of bacteria has an initial population of 7100 bacteria and doubles every 2
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Answer:

Pt=1285237.2855≈ 1285237

YOUR WELCOME :)

3 0
3 years ago
Pls help me out ty..
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Answer:

3.14159265359

Step-by-step explanation:

Hope this helps :)

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Read 2 more answers
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