101.19 / 4 using long division

A license plate has six characters. Three characters are letters, two characters are numbers (0-9), and one character is a lette

jok3333 [9.3K]

Answer:1)Number of different license plates can be made =17576×100×260=456976000

2)Probability of getting a plate with abc123 or 123 abc=0.0000004

Given that :-A license plate has six characters.

As three characters are letters ∴ ways of these 3 letters into the plate with repetition = 26×26×26=17576 ways

and two characters are numbers (0-9 - total 10 characters)∴ways of these 2 numbers into the plate with repetition=10×10 =100 ways

and one character is a letter or a number=26×10=260

So number of different license plates can be made =17576×100×260=456976000

Now Probability of getting a plate with abc123 or 123 abc

=P(abc123 or 123abc)=P(abc123)+P(123abc)-P(abc123)×P(123abc)=1/456976000+1/456976000-1/456976000×1/456976000

=1/456976000(1+1-1/456976000)

=1/456976000(2-0.0000002)=2/456976000=0.0000004

Probability of getting a plate with abc123 or 123 abc=0.0000004

3 0

2 years ago

Help plsssssssssssssss

avanturin [10]

Answer:step 2

Step-by-step explanation:

3 0

2 years ago

What is the system of inequalities associated with the following graph?

slamgirl [31]

One line passes through the points (-2,3) and (0,-3) , it means the y intercept is b=-3

and slope m = $\frac{(-3-3)}{0-(-2)}$

$= \frac{-6}{2}= -3$

So the equation of line will be $y= -3x -3$

And the inequality should be $y\geq -3x-3$

Or $3x +y \geq -3$

And the other line passes through (-2,3) and (0,2)

So the y intercept is b=2

and the slope is $m= \frac{2-3}{0-(-2)} = \frac{-1}{2}$

So the equation of line will be $y= \frac{-1}{2} x +2\\and the inequality should be y \leq \frac{-1}{2} x+2$

Or

$2y +x \leq 4$

So answer is $3x +y \geq -3, x+2y\leq 4$

6 0

3 years ago

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HELP!!!!! I do not understand how to do this! Could someone please explain to me how I would solve this problem?

maks197457 [2]

Yeah man nearly there

3 0

2 years ago

Please simplify this fraction c:

Liula [17]

F you just want to see the really short way, just skip down to AAAAAAAAAAAA

so, here is the long explanation
exponential properties
$x^{-m}= \frac{1}{x^m}$

don't forget pemdas
2x^2=2(x^2)

so
$\frac{2x^{-4}}{3xy}$ = $\frac{2 \frac{1}{x^4} }{3xy}= \frac{2}{3x^5y}$

AAAAAAAAAAAAAAAAAAAAAAAA
so we see
the original equatio is
$\frac{2x^{-4}}{3xy}$

remember
$\frac{ab}{cd} =( \frac{a}{c})( \frac{b}{d})$

so we can seperate the constants
$\frac{ab}{cd} =( \frac{2}{3})( \frac{x^{-4}}{xy})$

we know that the placeholders cannot affet the position of the constants unless they are grouped together which they are not

terfor the answer must have 2/3 in it

the only one that hsa that is A

ANSWER IS A

3 0

2 years ago

Read 2 more answers