Question

Find me equation of the circle with Center at ( 3, - 2) and radius of 3

Answer 1

The equation of a circle with center $(x_0,y_0)$ and radius $r$ is

$(x-x_0)^2+(y-y_0)^2=r^2$

In your case,

$x_0=3,\quad y_0=-2,\quad r=3$

Plug these values into the generic formula and you'll get your equation.