Answer:
The probability that the die will land on 1 and then 6 is 2.77%.
Step-by-step explanation:
Given that a fair sided die is rolled twice, to determine what is the probability It will land on 1 and then 6 the following calculation must be performed:
1/6 x 1/6 = X
0.166666 x 0.166666 = X
0.0277777 = X
0.0277777 x 100 = 2.77
Therefore, the probability that the die will land on 1 and then 6 is 2.77%.
The first one has a quotient greater than 15
The answer would be L because it is away from the rest ( outlier)
Straight line:
y = mx + c
m is the slope of the graph and c is the y-intercept
In this case, m = 5 as stated in the question, so...
y = 5x + c
By substituting the given co-ordinates (-2,-1) into this equation, we can find c
-1 = 5(-2) + c
-1 = -10 + c
-1 + 10 = -10 + c + 10 (Add 10 to both sides)
9 = c
c = 9
Put c = 9 into the equation:
y = 5x + 9
