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2 years ago

How are the values of -4^3 and 4^-3 alike and how do they differ?

Mathematics

1 answer:

BartSMP [9]2 years ago

4 0

Answer:

(-4)³ = -64

(4)⁻³ = 1/64

Step-by-step explanation:

$( - 4) {}^{3} = ( - 4) \times ( - 4) \times ( - 4) = - 64 \\$

${4}^{ - 3} = (\frac{1}{4} ) {}^{3} \\$

$({ \frac{1}{4} )}^{3} = \frac{1}{4} \times \frac{1}{4} \times \frac{1}{4} = \frac{1}{64} \\$

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After a hurricane, the Johnsons had 6 inches of water in their basement that was being pumped out at a rate of 1 inch per hour.

iren2701 [21]

Answer:

6>5

Step-by-step explanation:

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2 years ago

A praying mantis is an interesting insect that can rotate its head 180 degrees.Suppose the praying mantis at the right is 10.5 c

Charra [1.4K]

10.5 = 10 1/2 explanation is 1÷2 =0.5

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3 years ago

Read 2 more answers

What's (7x/2-5x+3)+(2x/2+4x-6)

Anika [276]

I'm assuming that when you wrote "(7x/2-5x+3)+(2x/2+4x-6)," you actually meant "(7x^2-5x+3)+(2x^2+4x-6). Correct me if I'm wrong here.

+(7x^2-5x+3)
+(2x/2+4x-6)
-------------------
=9x^2 - x - 3 (answer)

5 0

2 years ago

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

Answer:

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

Solution:

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

7 0

2 years ago

What is 1 - 1/6 * 3/2 =

kolezko [41]

1-1/6*3/2

multiply the two fractions

1/6*3/2

Cross out 3 and 6, divide by 3.

1/2 * 1/2

multiply the numerators together

1*1=1

multiply the denominators together

2*2=4

1-1/4

pretend that 1 has a denominator which is 1

1/1-1/4

find the common denominator for 1/1 which is 4

multiply by 4 for 1/1

1*4/1*4=4/4

4/4-1/4

Answer:

3/4

4 0

3 years ago