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dsp73
2 years ago
10

I have two questions.

Mathematics
1 answer:
Vanyuwa [196]2 years ago
7 0
1. Since M is the midpoint, then AM = MB.
2x + 5 = 5x - 22
3x = 27
x = 9.

2. Since M is the midpoint, then QM = MR.
<span>2x + 5 = 5x - 1
3x = 6
x = 2
QR = QM + MR 
QR = 2x + 5 + 5x - 1
QR = 7(2) + 4
QR = 18 units</span>
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How many even 3-digit positive integers can be written using the digits 1,2,4,7, and 8?
N76 [4]

Looking at the question, we can see we have 5 different numbers that can go in any order.

<u>5</u> * <u>4</u> * <u>3</u>

The above is basically saying there are 5 different numbers that can be multiplied by 4 other numbers. Those 2 can be multiplied by 3 different ones, leaving us with a 3 digit positive integer.

5 * 4* 3 = 60

4 0
2 years ago
Twenty students are members of the school debate team. Five
harkovskaia [24]

Answer:

75%

Step-by-step explanation:

\frac{15}{20} as a percent = 75%, or 0.75 in decimal form.

8 0
2 years ago
Plzzzzzzzzzzz Help me
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-3 < 0  Because -3 is less than 0.

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3 0
3 years ago
Read 2 more answers
The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term
Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be 1, 5, and 25.

The sum of the first seven terms of the geometric sequence would be 127.

Step-by-step explanation:

<h3>1.</h3>

Let d denote the common difference of the arithmetic sequence.

Let a_1 denote the first term of the arithmetic sequence. The expression for the nth term of this sequence (where n\! is a positive whole number) would be (a_1 + (n - 1)\, d).

The question states that the first term of this arithmetic sequence is a_1 = 1. Hence:

  • The third term of this arithmetic sequence would be a_1 + (3 - 1)\, d = 1 + 2\, d.
  • The thirteenth term of would be a_1 + (13 - 1)\, d = 1 + 12\, d.

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let r denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d.

Ratio between the third term and the second term of the geometric sequence:

\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}.

Both (1 + 2\, d) and \left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right) are expressions for r, the common ratio of this geometric sequence. Hence, equate these two expressions and solve for d, the common difference of this arithmetic sequence.

\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}.

(1 + 2\, d)^{2} = 1 + 12\, d.

d = 2.

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be 1, (1 + (3 - 1) \times 2) = 5, and (1 + (13 - 1) \times 2) = 25, respectively.

These three terms (1, 5, and 25, respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be r = 25 /5 = 5.

<h3>2.</h3>

Let a_1 and r denote the first term and the common ratio of a geometric sequence. The sum of the first n terms would be:

\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}.

For the geometric sequence in this question, a_1 = 1 and r = 25 / 5 = 5.

Hence, the sum of the first n = 7 terms of this geometric sequence would be:

\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}.

7 0
2 years ago
132% of what number is 25 nearest tenth
trapecia [35]

Answer:

100%

Step-by-step explanation:

3 0
3 years ago
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