Given:
The figure of a triangle LMN.
P is the centroid of triangle LMN.
To find:
14. Find the value of PN if QN=30.
15. Find the value of PN if QN=9.
Solution:
We know that the centroid in the intersection of medians of a triangle and centroid divides each median in 2:1.
Since P is the centroid it means NQ is the median from vertex N. It means P divides the median NQ in 2:1. So, PN:PQ=2:1.
14. We have QN=30.
Therefore, the value of PN is 20 when QN=30.
15. We have QN=9.
Therefore, the value of PN is 6 when QN=9.
Answer:
the answer is b.
Step-by-step explanation:
The expression for the height is (3k - 5)
Factorise the equation 6k^2 - 13k + 5
One is given : (2k-1). When factorising, you must make sure that you are obtaining the given equation.
Here, to get 6k^2, 2k is multiplied with 3k. The other factor is (3k-x)
Now, let's find x. From the factors (2k-1) (3k-x) how to obtain 13k?? Simple...
3k×-1 + 2k×x = 13k
-3k + 2kx = 13k
-3k + 2k(-5) = -3k + -10k = 13k
So the other expression is (3k-5) which is the height.
For this case we must find the value of the following expression:
We have to:
Substituting:
By definition of properties of powers and roots we have:
![\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%20%5E%20m%7D%20%3D%20a%20%5E%20%7B%5Cfrac%20%7Bm%7D%20%7Bn%7D%7D)
So:
So we have to:
Answer:
Option A
