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marusya05 [52]
3 years ago
7

Use long division to find the quotient below.

Mathematics
2 answers:
lawyer [7]3 years ago
7 0
The answer is c I might be wrong
JulijaS [17]3 years ago
5 0
Long polynomial division ~
Answer-
B. 8x2-4x+12
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The graph of a linear equation has a slope of -2 and passes through the point (-4,3) what is the equation of the line
valentinak56 [21]

Answer:

I need points

Step-by-step explanation:

nononon

3 0
3 years ago
Explain how to use the Distributive Property to simplify the left side of
zlopas [31]

Answer:

4a + 4(3) = 15

4a = 15 - 12

a = ¾

5 0
3 years ago
Select the correct answer. The volume of one of the Great Lakes is 3. 5 × 103 cubic kilometers. If there are 6. 3 × 107 fish in
valentinak56 [21]

The average number of fish per cubic kilometer is 1. 8 \times 10^4.

The correct option is B.

Given

The volume of one of the Great Lakes is 3.5 × 103 cubic kilometers.

The number of fish in the lake = 6. 3 × 107.

<h3>What is the average value?</h3>

The average is the middle value of the given data set and is calculated by adding up all the numbers and dividing the result by the total quantity of figures added.

The average number of fish per cubic kilometer is given by;

\rm \text{The average number of fish per cubic kilometer}= \dfrac{Number \ of \ fish \ in \ lake}{Total \ volume \ of \ lake}

Substitute all the values in the formula;

\rm \text{The average number of fish per cubic kilometer}= \dfrac{Number \ of \ fish \ in \ lake}{Total \ volume \ of \ lake}\\\\ \text{The average number of fish per cubic kilometer}= \dfrac{6.3\times 10^7}{3.5\times 10^3}\\ \text{The average number of fish per cubic kilometer}= 1.8 \times 10^4

Hence, the average number of fish per cubic kilometer is 1. 8 \times 10^4.

To know more about the Average rate click the link given below.

brainly.com/question/12395856

5 0
2 years ago
6.) *
labwork [276]

Answer:

the common difference is 5.4 and yes, this is an arithmetic sequence

Step-by-step explanation:

Each new term is derived by adding 5.4 to the previous term:

2.1 + 5.4 = 7.5,

7.5 + 5.4 = 12.9,

and so on,

so the common difference is 5.4 and yes, this is an arithmetic sequence.

8 0
3 years ago
Which equation represents a hyperbola with a center at (0, 0), a vertex at (−48, 0), and a focus at (50, 0)?
Lerok [7]

bearing in mind that "a" is the length of the traverse axis, and "c" is the distance from the center to either foci.

we know the center is at (0,0), we know there's a vertex at (-48,0), from the origin to -48, that's 48 units flat, meaning, the hyperbola is a horizontal one running over the x-axis whose a = 48.

we also know there's a focus point at (50,0), that's 50 units from the center, namely c = 50.


\bf \textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2}\\ \textit{asymptotes}\quad y= k\pm \cfrac{b}{a}(x- h) \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}


\bf \begin{cases} h=0\\ k=0\\ a=48\\ c=50 \end{cases}\implies \cfrac{(x-0)^2}{48^2}-\cfrac{(y-0)^2}{b^2}=1 \\\\\\ c=\sqrt{a^2+b^2}\implies \sqrt{c^2-a^2}=b\implies \sqrt{50^2-48^2}=b \\\\\\ \sqrt{196}=b\implies 14=b~\hspace{3.5em}\cfrac{(x-0)^2}{48^2}-\cfrac{(y-0)^2}{14^2}=1\implies \cfrac{x^2}{48^2}-\cfrac{y^2}{14^2}=1

8 0
3 years ago
Read 2 more answers
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